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POReturn promise to use with ajax object
 

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    <p>I have a function that I pass a <code>form</code> element into in order to handle form submits using AJAX.</p> <p>I want to return the ajax object that will be handling the form submit from my function so that I can attach additional <code>done</code> callbacks -- the problem is I don't know how to return the ajax object without creating it(and executing it) first. </p> <p>How can I substitute a promise in lieu of the actual ajax object so that I return something to attach extra callbacks to?</p> <pre><code>HandleModalFormSubmit: function (element) { var form, modalcontainer = $(element).closest('.modal'), modal = $(element).closest('.modal-dialog'), ajaxdata; if (element.is('form')) form = $(element); else { form = element.find('form'); } $.validator.unobtrusive.parse(form); $(element).on('submit', function (event) { event.preventDefault(); ajaxdata = $.ajax({ type: form.method, url: form.action, data: $(form).serialize() }).done(function (data) { if (data.status == null) { modal.html(data); } else { modalcontainer.modal('hide'); }; }).always(function (data) { modal.spin(false); modal.fadeTo(500, 1); }); modal.fadeTo(300, 0); modal.spin(); }); var returningobject = { element: form, ajax: ajaxdata }; return returningobject; } } </code></pre> <p>EDIT: Here is what I'd like to have happen with the function</p> <pre><code> var formobject = $Global.HandleAjaxForm(element); formobject.ajax.done(function(data1) { if (data1.status == 'ok') window.location.href = (data.redirectToUrl == null) ? "~/Dashboard" : data.redirectToUrl; }); </code></pre>
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    1. USMatt Foxx Duncan
    1. USMatt Foxx Duncan
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