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    <p>So, let me get this straight, you have N text fields of differing widths and you want to remove 1 or more of them, rearranging the remaining M text fields, redistributing their widths proportionally (i.e. so if text field T<sub>1</sub> was twice the width of text field T<sub>2</sub>, it would still be after they are rearranged)?</p> <p>This isn't actually a very simple problem, but I've taken a stab at it below. You pass it the array of your text fields (from left to right), the number you want to keep, and an optional X-offset.</p> <p><strong>Note:</strong> I haven't done AS3 in months so consider the below to be pseudocode--you will have to edit it to make it work.</p> <pre><code>function arrangeTextFields(textFields:Array, keep:int, xOffset:Number = 0) { // we can't keep more fields than are provided keep = Math.min(keep, textFields.length); var totalWidth = 0, // the total width of all textfields keptOrigWidth = 0, // the total combined widths of the ones you're keeping origNum:int = textFields.length; // calculate the above values by addition in a loop // (because AS3 lacks an inject/reduce method) for(var i:int, i++, i &lt; origNum) { totalWidth += textFields[i].width; if(i &lt; take) { keptOrigWidth += textFields[i].width; } } var ratio:Number = totalWidth / takenOrigWidth, // the ratio we'll resize each field by to keep them proportional currentX:int = 0; textFields = textFields.slice(0, keep - 1); // throw away the fields we're not keeping for(int i = 0; i &lt; take; i++) { textFields[i].width = textFields[i].width * ratio; // resize it textFields[i].x = currentX + xOffset; // move it currentX += textFields[i].width; } } </code></pre> <p><strong>Note:</strong> This code doesn't actually remove the "unkept" text fields from view; you'll have to add that or do it elsewhere.</p>
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