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POMethod within a while loop
 

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  1. POMethod within a while loop
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    <p>Specifically, in the while loop there is some logic area that is not allowing the program to flow correctly. I have walked through this loop and it should work. Some of the errors I am having is when I enter "0" it doesn't exit right away, other words I have to press 0 twice which doesn't make sense to me unless I am not comprehending the while loop correctly. The other error is in my add () method, what ever I enter it only tells me the first number I inputted. So I am fairly certain the error is in my loop, but I can't see where the logic error is coming from. Any help would be appreciated, thank you.</p> <pre><code>import javax.swing.JOptionPane; public class RandyGilmanP2 {//Begin class public static void main(String[] args) {//Begin main JOptionPane.showMessageDialog(null, "Hello Welcome to Sum and Average" + "\n of a Number Calculator Program" + "\n By: Randy Gilman"); //Declare variables float add = 0;//used to store the sum of the numbers inputed float numb = input();//used to store the value of Input() method float average; int count = 0;// Used as a counter variable //Loop that will be controlled by a sentenil value while (numb != 0) {//Begin for loop count += 1; //Call Input method input(); numb = input(); //Method to find the sum of all the numbers inputed sum(add,numb); add = sum(add,numb); //Used to find the average of all the numbers entered (sum / count) }//End for loop avg(add,count); average = avg(add,count);//used to store the average of the numbers Results(count,add,average); }//End Main public static float input(){//Begin Method //Will keep gathering input from user until input is equal to 0 String NumberString = JOptionPane.showInputDialog("Enter a floating point number" + "(The program ends when 0 is entered):"); //Convert string to float float number = Float.parseFloat(NumberString); return number; }//End Method public static float sum(float sum, float numb2){//Begin method //Add number to the previous number to compute total sum += numb2; if (sum &gt; 100) JOptionPane.showMessageDialog(null, "***WARNING***" + "\n The sum of your numbers exceed 100"); return sum; }//End Method public static float avg(float num1, float num2){ //Declare variables float result; //Preform calculation of average result = num1 / num2; return result; }//End Method public static void Results(int counter, float addition, float aver){//Begin method //Declare variables JOptionPane.showMessageDialog(null,"The total amount of numbers you entered are: " + counter); JOptionPane.showMessageDialog(null,"The sum of the numbers you have entered is: " + addition); JOptionPane.showMessageDialog(null,"The average of the numbers you have entered is: " + aver); }//End Method }//End Class </code></pre>
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    1. COYou cannot compare a float against an absolute value. Rounding errors will trip you up.
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      1. USJohan
    2. CO@Johan: Unless the `parseFloat` method is broken (unlikely), it will return an exact floating point representation of zero, so the comparison is not the problem. Floats represent integers exactly until the significand runs out of bits, so single-precision (with 23 bits of significand and an implied extra bit) can exactly represent integers from -2^24 to 2^24.
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      1. USsfstewman
 

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