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    <p>You cannot pass variable values from the current page javascript to the current page PHP code... PHP code runs at the server side and it doesn't know anything about what is going on on the client side.</p> <p>You need to pass variables to PHP code from html-form using another mechanism, such as submitting form on GET or POST methods.</p> <pre><code>&lt;DOCTYPE html&gt; &lt;html&gt; &lt;head&gt; &lt;title&gt;My Test Form&lt;/title&gt; &lt;/head&gt; &lt;body&gt; &lt;form method="POST"&gt; &lt;p&gt;Please, choose the salary id to proceed result:&lt;/p&gt; &lt;p&gt; &lt;label for="salarieids"&gt;SalarieID:&lt;/label&gt; &lt;?php $query = "SELECT * FROM salarie"; $result = mysql_query($query); if ($result) : ?&gt; &lt;select id="salarieids" name="salarieid"&gt; &lt;?php while ($row = mysql_fetch_assoc($result)) { echo '&lt;option value="', $row['salaried'], '"&gt;', $row['salaried'], '&lt;/option&gt;'; //between &lt;option&gt;&lt;/option&gt; tags you can output something more human-friendly (like $row['name'], if table "salaried" have one) } ?&gt; &lt;/select&gt; &lt;?php endif ?&gt; &lt;/p&gt; &lt;p&gt; &lt;input type="submit" value="Sumbit my choice"/&gt; &lt;/p&gt; &lt;/form&gt; &lt;?php if isset($_POST['salaried']) : ?&gt; &lt;?php $query = "SELECT * FROM salarie WHERE salarieid = " . $_POST['salarieid']; $result = mysql_query($query); if ($result) : ?&gt; &lt;table&gt; &lt;?php while ($row = mysql_fetch_assoc($result)) { echo '&lt;tr&gt;'; echo '&lt;td&gt;', $row['salaried'], '&lt;/td&gt;&lt;td&gt;', $row['bla-bla-bla'], '&lt;/td&gt;' ...; // and others echo '&lt;/tr&gt;'; } ?&gt; &lt;/table&gt; &lt;?php endif?&gt; &lt;?php endif ?&gt; &lt;/body&gt; &lt;/html&gt; </code></pre>
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    1. POHow to pass JavaScript variables to PHP?
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    1. USSergey Kuznetsov
    1. USSergey Kuznetsov
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    1. POHow to pass JavaScript variables to PHP?
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      1. VTUpMod
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    1. CO@Sergey, I have used submitting form here with POST method, i don't know why it doesn't work. Do you know why? And how to solve that?
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      1. USJiangong SUN
    2. CO@sergey, so i need to use ajax? Actually, i'm familliar with that.
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      1. USJiangong SUN
    3. COActually, I have used your method in the past one level select box. But now i have made a three-chained select box, so i can't use your method.
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      1. USJiangong SUN
 

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