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POHow to write a program that use 2D array to generate a matrix?
 

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  1. POHow to write a program that use 2D array to generate a matrix?
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    <p>Suppose user enter a integer "3", the matrix should 3 X 3 and some random numbers in it. For example: </p> <pre><code>8 0 2 6 3 4 5 7 1 </code></pre> <p>I need to use 2D array to do it.</p> <p>But I have no idea about how to finish it. Here is my code, what should I do now?</p> <pre><code>#include "stdafx.h" #include "stdlib.h" #include "time.h" int _tmain(int argc, _TCHAR* argv[]) { int num1, num2; printf("enter a integer (3-9): "); scanf("%d", &amp;num1); srand(time(NULL)); switch (num1) { case 3: num2 = (rand() % 8); break; case 4: num2 = (rand() % 15); break; case 5: num2 = (rand() % 24); break; case 6: num2 = (rand() % 35); break; case 7: num2 = (rand() % 48); break; case 8: num2 = (rand() % 63); break; case 9: num2 = (rand() % 80); break; } printf("%d %d\n", num1, num2); int s[][] = num1 * num1; return 0; } </code></pre> <hr> <p>New update</p> <pre><code>#include "stdafx.h" #include "stdlib.h" #include "time.h" int _tmain(int argc, _TCHAR* argv[]) { int num2 = 0; int num=0, i, j; int mtx[9][9] = {0}; while (num &lt; 3 || num &gt; 9) { printf("Enter an integer (3-9): "); scanf("%d", &amp;num); } do { srand(time(NULL)); switch (num) { case 3: num2 = rand() % 8; break; case 4: num2 = rand() % 15; break; case 5: num2 = rand() % 24; break; case 6: num2 = rand() % 35; break; case 7: num2 = rand() % 48; break; case 8: num2 = rand() % 63; break; case 9: num2 = rand() % 80; break; } for (i=0; i &lt; num; ++i) for (j=0; j &lt; num; ++j) mtx[i][j] = num2; } while ( num2 == num2); for (i=0; i &lt; num; ++i) { for (j=0; j &lt; num; ++j) printf("%i ", mtx[i][j]); printf("\n"); } return 0; } </code></pre>
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      1. POHow to write a program that use 2D array to generate a matrix?
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    1. COYou can replace that entire `switch` statement with the line `num2 = rand() % ((num1 * num1) - 1);`.
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