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    <p>Well... Here's a script I made for MD5 brute forcing that maxes out the RAM in an hour or so...</p> <pre><code>using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Security.Cryptography; namespace csharp { class Program { public static string[] letters = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "1", "2", "3", "4", "5", "6", "7", "8", "9", "0" }; static void Main(string[] args) { //string mg = MD5Hash("john"); bool inp = false; string hash; while (!inp) { Console.WriteLine("Please input the hash you're trying to bruteforce..."); hash = Console.ReadLine(); if (hash.Length == 32) { inp = true; Console.WriteLine("Cracked! There you go: " + startProcess(hash)); Console.ReadLine(); } } } public static string startProcess(string hsh) { bool solved = false; string track = letters[0]; string ltrack = letters[letters.Length - 1]; while (!solved) { //Console.WriteLine(track); // remove this line for debug track = setLCharPos(track, ltrack); if (MD5Hash(track) == hsh) { solved = true; return track; } } return track; } public static string setLCharPos(string ttr, string ltr) { if (ttr == "") return letters[0]; if (ttr[ttr.Length - 1].ToString() != ltr) { return ttr.Substring(0, ttr.Length - 1) + letters[Array.IndexOf(letters, ttr[ttr.Length - 1].ToString()) + 1]; } else { return setLCharPos(ttr.Substring(0, ttr.Length - 1), ltr) + letters[0]; } } public static string MD5Hash(string text) { MD5 md5 = new MD5CryptoServiceProvider(); //compute hash from the bytes of text md5.ComputeHash(ASCIIEncoding.ASCII.GetBytes(text)); //get hash result after compute it byte[] result = md5.Hash; StringBuilder strBuilder = new StringBuilder(); for (int i = 0; i &lt; result.Length; i++) { //change it into 2 hexadecimal digits //for each byte strBuilder.Append(result[i].ToString("x2")); } return strBuilder.ToString(); } } } </code></pre> <p>Just insert any 32 character string and it will loop forever. Unless you actually are trying to bruteforce, I take no responsibility for this.</p>
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