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POHow to discover if 2 CGPath roteted rects intersect?
 

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  1. POHow to discover if 2 CGPath roteted rects intersect?
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    <p>I am building 2 rects when view controller is loaded, using <code>CGPath</code>. The rects can be moved with <code>PanGestureRecognizer</code>. The question is how can I know when 2 rects had met? In order to not let them intersect?</p> <p><strong>MainViewController.m</strong></p> <pre><code>- (void)viewDidLoad { [super viewDidLoad]; for (int i=0; i&lt; 2; i++) { //create rects of CGPath CGRectCustomView* randomColorRect = [[CGRectCustomView alloc]initWithFrame: CGRectMake(&lt;random place on screen&gt;)]; //random angle randomColorRect.transform = CGAffineTransformMakeRotation (DegreesToRadians([Shared randomIntBetween:0 and:360])); [self.view addSubview:randomColorRect]; } } - (BOOL)areRectsCollide { ???How to find this??? } </code></pre> <p><strong>CGRectCustomView.m:</strong></p> <pre><code>- (void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSetLineWidth(context, 8.0); CGContextStrokePath(context); // do actual stroking CGContextSetRGBFillColor(context, &lt;green color&gt;, 1); CGContextFillRect(context, CGRectMake(self.frame.origin.x, self.frame.origin.y, self.frame.size.width, self.frame.size.height)); path = CGContextCopyPath(context); } </code></pre> <p>In Apple guide <a href="https://developer.apple.com/library/ios/documentation/2DDrawing/Conceptual/DrawingPrintingiOS/BezierPaths/BezierPaths.html" rel="nofollow">here</a>, there is a function that determines if a path contains point </p> <p><code>- (BOOL)containsPoint:(CGPoint)point onPath:(UIBezierPath *)path inFillArea:(BOOL)inFil</code>,</p> <p>but I have a rectangle which is endless number of points. So what should I do? Breaking my head... </p>
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    1. COA rectangle has an "endless number of points"? These must be really strange rectangles...
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      1. POHow to discover if 2 CGPath roteted rects intersect?
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    2. CO@bummzack Any line/area consists of endless number of points. At least in my perception of geometry. But I may be wrong :)
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    3. CODoh! You're right of course.
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