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  1. PO
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    <p><strong>EDIT1 :</strong> Sorry, I forgot about the spaces management : here is <strong>a</strong> solution:</p> <pre><code>SET serveroutput ON format wraped; DECLARE l_text varchar2(64) := 'Tristram Vladimir Chan'; l_mask VARCHAR2(64) := '.....XXXX..XX.....X.XX'; l_res VARCHAR2(64); l_text_length INTEGER := length(l_text); l_mask_length INTEGER := length(l_mask); l_pos INTEGER := 1; l_p INTEGER := -1; l_x INTEGER := -1; l_b INTEGER := instr(l_text, ' '); l_lastb INTEGER := 0; l_cpt INTEGER := 1; BEGIN -- in case text length doesn't match mask length if l_mask_length &gt; l_text_length then l_mask := substr(l_mask, 1, l_text_length); elsif l_text_length &gt; l_mask_length then l_mask := rpad(l_mask, l_text_length, '.'); end if; l_mask_length := l_text_length; -- loop for each sequence of characters in the mask while l_pos &lt;= l_mask_length loop l_p := instr(l_mask, '.'); -- first '.' position l_x := instr(l_mask, 'X'); -- first 'X' position -- if "." or "X' has not been found if l_p = 0 or l_x = 0 then if l_p = 0 then -- no "." found, write 'X' until the end l_res := rpad(l_res, l_text_length, 'X'); elsif l_x = 0 then -- no "X" found, write text until the end l_res := l_res || substr(l_text, l_pos, l_text_length); end if; l_pos := l_mask_length+1; else if l_p = 1 then -- '.' found, write text until the next 'X' l_res := l_res || substr(l_text, l_pos, l_x-1); l_mask := substr(l_mask, l_x); l_pos := l_pos + l_x-1; elsif l_x = 1 then -- 'X' found, write 'X' until the next '.' l_res := rpad(nvl(l_res,'X'), nvl(length(l_res),0)+l_p-1, 'X'); l_mask := substr(l_mask, l_p); l_pos := l_pos + l_p-1; end if; end if; -- if a ' ' is found in the original text, replace it in the result if l_pos &gt; l_b and l_b &gt; l_lastb then l_b := instr(l_text, ' ', 1, l_cpt); l_res := substr(l_res, 1, l_b-1) || ' ' || substr(l_res,l_b+1,length(l_res)); l_lastb := l_b; l_cpt := l_cpt + 1; end if; end loop; dbms_output.put_line(l_res); END; </code></pre> <p>Result : <code>TristXXX VlXXimir XhXX</code></p> <p>It may be possible to improve it, I just wrote it "procedurally". The advantage compared to other solutions, is that here you can change the mask.</p> <p><strong>EDIT2</strong> : I reworked the code, it is pretty much simpler... :</p> <pre><code>SET serveroutput ON format wraped; DECLARE l_text varchar2(64) := 'Tristram Vladimir Chan'; l_mask VARCHAR2(64) := '.....XX..XX....XXXX...'; l_res VARCHAR2(64); l_text_length INTEGER := length(l_text); l_mask_length INTEGER := length(l_mask); l_pos INTEGER := 1; BEGIN -- in case text length doesn't match mask length if l_mask_length &gt; l_text_length then l_mask := substr(l_mask, 1, l_text_length); elsif l_text_length &gt; l_mask_length then l_mask := rpad(l_mask, l_text_length, '.'); end if; l_mask_length := l_text_length; -- loop and build the result string while l_pos &lt;= l_mask_length loop if substr(l_mask, l_pos, 1) = 'X' then l_res := l_res || 'X'; else l_res := l_res || substr(l_text, l_pos, 1); end if; if substr(l_text, l_pos, 1) = ' ' then l_res := substr(l_res, 1, l_pos-1) || ' '; end if; l_pos := l_pos + 1; end loop; dbms_output.put_line(l_res); END; </code></pre> <p>Result : <code>TristXXm XXadimXX Xhan</code></p>
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    1. POHow to mask characters with X in a varchar2 field in Oracle SQL
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    1. COthanks. the result does not contain the spaces. is there a way to fix this?
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    2. COAh sorry, yes of course. I will update my post ;)
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    3. CO@Din you should accept an answer.
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