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    <p>You don't really need PL/SQL for this; you can use <code>regexp_substr</code>:</p> <pre><code>select count(distinct value) from ( select regexp_substr(interfaceline, '[^|]+', 1, :arrayPos) as value from inttestintrecs where sessionid between :loSessId and :hiSessId ); </code></pre> <p>... where the bind variables are the values you were passing to the function. If you really want a function for that you can just wrap the query (updated with tbone's <code>replace</code> trick to deal with null values):</p> <pre><code>create or replace function DistinctInterfacelineValues( inArrayPos NUMBER, inSessionIdMIN NUMBER, inSessionIdMAX NUMBER) RETURN NUMBER AS distinctCount NUMBER; BEGIN select count(distinct value) into distinctCount from ( select trim(regexp_substr(replace(interfaceline, '|', ' |'), '[^|]+', 1, inArrayPos)) as value from inttestintrecs where sessionid between inSessionIdMIN and inSessionIdMAX ); RETURN distinctCount; END; / </code></pre> <p><a href="http://sqlfiddle.com/#!4/85409/1" rel="nofollow">SQL Fiddle demo</a>.</p> <hr> <p>Within the nested loop version you posted, you <em>could</em> maintain a PL/SQL table indexed by the value rather than a number:</p> <pre><code>... TYPE table_type IS TABLE OF NUMBER INDEX BY VARCHAR2(100); tempTable table_type; tempValue VARCHAR2(100); ... IF i = inArrayPos THEN tempValue := regexp_substr(int_record.interfaceline, '[^|]+', 1, i); tempTable(tempValue) := 1; END IF; ... RETURN tempTable.count; ... </code></pre> <p><a href="http://sqlfiddle.com/#!4/76073/1" rel="nofollow">Another Fiddle</a> just for fun, but there's really no point having all the PL/SQL loop overhead, particularly with the <code>regexp_substr</code> in the middle anyway. You could increment the count held in <code>tempTable</code> for each value so you knew how many of each you'd seen, and you could get the actual values from <code>tempTable</code> too... but you can get those from the pure SQL version just as easily (selecting <code>value, count(*)</code> and <code>distinct value</code>).</p>
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    1. COThanks @AlexPoole, really appreciate it.
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    2. COOne other very quick question if I may
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    3. CO@Mike- I looked at your follow-up question and couldn't see a quick fix; but tbone's answer to that works - [Fiddle](http://sqlfiddle.com/#!4/65d33/3). I updated the answer to include that too.
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