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    <pre><code>str.replace(/([.?!])\s*(?=[A-Z])/g, "$1|").split("|") </code></pre> <p>Output:</p> <pre><code>[ 'This is a long string with some numbers [125.000,55 and 140.000] and an end.', 'This is another sentence.' ] </code></pre> <p>Breakdown:</p> <p><code>([.?!])</code> = Capture either <code>.</code> or <code>?</code> or <code>!</code></p> <p><code>\s*</code> = Capture 0 or more whitespace characters following the previous token <code>([.?!])</code>. This accounts for spaces following a punctuation mark which matches the English language grammar.</p> <p><code>(?=[A-Z])</code> = The previous tokens only match if the next character is within the range A-Z (capital A to capital Z). Most English language sentences start with a capital letter. None of the previous regexes take this into account.</p> <hr> <p>The replace operation uses:</p> <pre><code>"$1|" </code></pre> <p>We used one "capturing group" <code>([.?!])</code> and we capture one of those characters, and replace it with <code>$1</code> (the match) plus <code>|</code>. So if we captured <code>?</code> then the replacement would be <code>?|</code>.</p> <p>Finally, we split the pipes <code>|</code> and get our result.</p> <hr> <p>So, essentially, what we are saying is this:</p> <p>1) Find punctuation marks (one of <code>.</code> or <code>?</code> or <code>!</code>) and capture them</p> <p>2) Punctuation marks can optionally include spaces after them.</p> <p>3) After a punctuation mark, I expect a capital letter.</p> <p>Unlike the previous regular expressions provided, this would properly match the English language grammar.</p> <p>From there:</p> <p>4) We replace the captured punctuation marks by appending a pipe <code>|</code></p> <p>5) We split the pipes to create an array of sentences.</p>
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    1. COThis solution fails if a sentence starts with a number.
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    2. COYou can modify it to this: /([.?!])\x20{1,2}(?=[A-Z\d])/. However, this would expect that A) decimal numbers do not have spaces after them, and B) there is either one or two space characters following a punctuation mark. This would conform with English grammar. If you cannot accept condition A, there would be an ambiguity in the grammar you are attempting to parse.
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    3. COMore on grammatical ambiguity in computer science: http://en.wikipedia.org/wiki/Ambiguous_grammar . Essentially, in your situation, numbers with a decimal separator and punctuation marks for new sentences need to be grammatically distinguishable. The revised regex I provided conforms with the English language grammar.
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