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POReplicate image in CSS and HTML only
 

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  1. POReplicate image in CSS and HTML only
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    <p>For a code quiz I am trying to replicate the attached image using CSS and HTML only. The gradients and borders seem to be working out fine, but I am having trouble getting the ribbon edges to look curved.</p> <p>Here is my markup:</p> <pre><code>&lt;div class="container"&gt; &lt;div class="ribbon-wrapper-green"&gt;&lt;div class="ribbon-green"&gt;AWESOME!&lt;/div&gt;&lt;/div&gt; &lt;div class="ribbon-bottom-left"&gt;&lt;/div&gt; &lt;div class="bottom-left-gradient"&gt;&lt;/div&gt; </code></pre> <p></p> <p>And here is my CSS:</p> <pre><code> .container { width:300px; height:300px; margin-left:auto; margin-right:auto; margin-top:10px; position:relative; border:#CCC 1px solid; background-color:#EBEBEB; box-shadow:1px 1px 1px #CCC; } .ribbon-wrapper-green { width: 290px; height: 290px; overflow: hidden; position: absolute; top: -3px; right: -3px; } .ribbon-green { font: 25px Arial; text-align: center; text-shadow:0px 0px 6px #000; -webkit-transform: rotate(45deg); -moz-transform: rotate(45deg); -ms-transform: rotate(45deg); -o-transform: rotate(45deg); position: relative; padding: 20px 0; left: 7px; top: 66px; width: 363px; background-color: #BFDC7A; background-image: -webkit-gradient(linear, left top, left bottom, from(#BFDC7A), to(#8EBF45)); background-image: -webkit-linear-gradient(top, #BFDC7A, #8EBF45); background-image: -moz-linear-gradient(top, #BFDC7A, #8EBF45); background-image: -ms-linear-gradient(top, #BFDC7A, #8EBF45); background-image: -o-linear-gradient(top, #BFDC7A, #8EBF45); color: #FFF; -webkit-box-shadow: 0px 8px 20px rgba(0,0,0,0.3); -moz-box-shadow: 0px 8px 20px rgba(0,0,0,0.3); box-shadow: 0px 8px 20px rgba(0,0,0,0.3); } .ribbon-green:before, .ribbon-green:after { content: ""; border-top: 4px solid #6e8900; border-left: 4px solid transparent; border-right: 4px solid transparent; position:absolute; bottom: -4px; } .ribbon-green:before { left: 0; } .ribbon-green:after { right: 0; } .ribbon-bottom-left { width: 0px; height: 0px; border-style: solid; border-width: 250px 0 0 250px; border-color: transparent transparent transparent #D32023; position:absolute; bottom:-5px; left:-5px; border-top-left-radius:10px; border-bottom-right-radius:10px; -moz-border-radius-topleft:10px; -moz-border-radius-bottomright:10px; z-index:1; } .bottom-left-gradient { position:absolute; bottom:-8px; left:-8px; z-index:100; height:245px; width:245px; opacity:0.4; filter:alpha(opacity=40); background: -moz-linear-gradient(45deg, rgba(255,255,255,1) 0%, rgba(255,255,255,0.92) 4%, rgba(255,255,255,0) 51%); /* FF3.6+ */ background: -webkit-gradient(linear, left bottom, right top, color-stop(0%,rgba(255,255,255,1)), color-stop(4%,rgba(255,255,255,0.92)), color-stop(51%,rgba(255,255,255,0))); /* Chrome,Safari4+ */ background: -webkit-linear-gradient(45deg, rgba(255,255,255,1) 0%,rgba(255,255,255,0.92) 4%,rgba(255,255,255,0) 51%); /* Chrome10+,Safari5.1+ */ background: -o-linear-gradient(45deg, rgba(255,255,255,1) 0%,rgba(255,255,255,0.92) 4%,rgba(255,255,255,0) 51%); /* Opera 11.10+ */ background: -ms-linear-gradient(45deg, rgba(255,255,255,1) 0%,rgba(255,255,255,0.92) 4%,rgba(255,255,255,0) 51%); /* IE10+ */ background: linear-gradient(45deg, rgba(255,255,255,1) 0%,rgba(255,255,255,0.92) 4%,rgba(255,255,255,0) 51%); /* W3C */ filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#00ffffff',GradientType=1 ); /* IE6-9 fallback on horizontal gradient */ border-style:solid; border-width:0 0 5px 5px; border-radius:10px; -moz-border-radius:10px; border-color:#E41316; } </code></pre> <p>The image is coming out like this example here: <a href="http://arunsood.me/code-quizzes/placebo-effect/" rel="nofollow noreferrer">http://arunsood.me/code-quizzes/placebo-effect/</a>.</p> <p>The original I need to copy is below. How can I achieve the edge bending effect via CSS alone?</p> <p><img src="https://i.stack.imgur.com/qPXBx.jpg" alt="Original Image"></p>
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    1. COIn order to replicate this you're going to need to use border-radius, box-shadow, border combined with gradients. Lastly to replicate the really dark shadows under the ribbon I would generate that with it's own html
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    2. CO@ColinMcGrath He already is using all of those.
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      1. USMr Lister
    3. CO@MrLister I see that, I was just running through how I would tackle it. I answered his question indirectly. Basically there is no easy way to achieve that wrap-around effect, just a lot of trial and error with css3
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