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    <p>You could define your external ID as extra property on your nodes. Then depending on if your are using SpringData or not, you can insert the data.</p> <p>If you are using SpringData, you can configure your external ID as unique index and then normally save you nodes(consider though, that inserting a duplicated ID will overwrite the existing one).</p> <p>If you are using the plain java API, you can create unique nodes as described here: <a href="http://docs.neo4j.org/chunked/stable/tutorials-java-embedded-unique-nodes.html#tutorials-java-embedded-unique-get-or-create" rel="nofollow">http://docs.neo4j.org/chunked/stable/tutorials-java-embedded-unique-nodes.html#tutorials-java-embedded-unique-get-or-create</a></p> <p>EDIT: As for a sample query, does this help you? <a href="http://console.neo4j.org/?id=b0z486" rel="nofollow">http://console.neo4j.org/?id=b0z486</a></p> <p>With the java api you would do it like this</p> <pre><code>firstNode = graphDb.createNode(); firstNode.setProperty( "externalID", "1" ); firstNode.setProperty( "name", "foo" ); secondNode = graphDb.createNode(); secondNode.setProperty( "externalID", "2" ); secondNode.setProperty( "name", "bar" ); relationship = firstNode.createRelationshipTo( secondNode, RelTypes.Likes ); </code></pre> <p>I suggest you read some tutorials here: <a href="http://docs.neo4j.org/chunked/stable/tutorials-java-embedded-hello-world.html" rel="nofollow">http://docs.neo4j.org/chunked/stable/tutorials-java-embedded-hello-world.html</a></p>
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    1. POUnderstanding Neo4j, creating unique nodes
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    1. COI updated my question. I'm not using Java, I need to use the REST api. In your example executing ` CREATE (_1 { name:"Foo" }),(_2 { name:"Bar" }), _1-[:LIKES]->_2` multiple times gives multiple independent node pairs.
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    2. COWell of course, NEo4j per default only enforces uniqueness on its internal IDs. If you are using REST and want to create unique nodes, maybe this is what you were looking for: http://docs.neo4j.org/chunked/stable/rest-api-unique-indexes.html
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    3. COBut this requires three roundtrips and takes the A out of ACID.
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