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POHow can i find the positions to the three lowest integers in an array?
 

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  1. POHow can i find the positions to the three lowest integers in an array?
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    <p>I how can I find the positions of the three lowest integers in an array? I've tried to reverse it, but when I add a third number, it all goes to hell :p Does anybody manage to pull this one off and help me? :)</p> <p>EDIT: It would be nice to do it without changing or sorting the original array a.</p> <pre><code>public static int[] lowerThree(int[] a) { int n = a.length; if (n &lt; 2) throw new java.util.NoSuchElementException("a.length(" + n + ") &lt; 2!"); int m = 0; // position for biggest int nm = 1; // position for second biggest if (a[1] &gt; a[0]) { m = 1; nm = 0; } int biggest = a[m]; // biggest value int secondbiggest = a[nm]; // second biggest for (int i = 2; i &lt; n; i++) { if (a[i] &gt; secondbiggest) { if (a[i] &gt; biggest) { nm = m; secondbiggest = biggest; m = i; biggest = a[m]; } else { nm = i; secondbiggest = a[nm]; } } } // for return new int[] {m,nm}; } </code></pre> <p>EDIT: I've tried something here but it still doesn't work. I get wrong output + duplicates...</p> <pre><code> public static int[] lowerthree(int[] a) { int n= a.length; if(n &lt; 3) throw new IllegalArgumentException("wrong"); int m = 0; int nm = 1; int nnm= 2; int smallest = a[m]; // int secondsmallest = a[nm]; / int thirdsmallest= a[nnm]; for(int i= 0; i&lt; lengde; i++) { if(a[i]&lt; smallest) { if(smalles&lt; secondsmallest) { if(secondsmallest&lt; thirdsmallest) { nnm= nm; thirdsmallest= secondsmallest; } nm= m; secondsmallest= smallest; } m= i; smallest= a[m]; } else if(a[i] &lt; secondsmallest) { if(secondsmallest&lt; thirdsmallest) { nnm= nm; thirdsmallest= secondsmallest; } nm= i; secondsmallest= a[nm]; } else if(a[i]&lt; thirdsmallest) { nnm= i; thirdsmallest= a[nnm]; } } return new int[] {m, nm, nnm}; } </code></pre>
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    1. CODefine hell please :)
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    2. COYou just need one more variable and one more `if`.
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    3. COIt's really easy and does not require any fancy stuff. You just have to think it through VERY CAREFULLY, resisting the urge to "just try something" and instead thinking out the logic at each step.
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