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POHow to work with Jpa in play framework?
 

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  1. POHow to work with Jpa in play framework?
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    <p>I am working with Play framework with JPA to store database but some issue is coming :</p> <p>what am i doing is i am storing user into database but exception is coming.</p> <p>My <strong>controller</strong> is:</p> <pre><code>public class Application extends Controller { @Transactional(readOnly=true) public static Result index() { Form&lt;Userd&gt; ud=form(Userd.class); return ok(index.render(ud)); } @Transactional public static Result enter(){ Form&lt;Userd&gt; crForm = form(Userd.class).bindFromRequest(); if(crForm.hasErrors()){ return badRequest(index.render(crForm)); } else{ crForm.get().save(); return ok("value saved"); } } } </code></pre> <p><strong>Model</strong> is:</p> <pre><code>@Entity public class Userd { @Required public String name; @Email public String email; @Id public Long empid; @Required public String password; public static Userd findById(Long id) { return JPA.em().find(Userd.class,id ); } public Userd() { } public Userd(String name, String email, Long empid, String password) { this.name = name; this.email = email; this.empid = empid; this.password = password; } public void save(){ JPA.em().persist(this); } </code></pre> <p>and <strong>Exception</strong> is:</p> <pre><code>[RollbackException: Error while committing the transaction] </code></pre> <p><strong>terminal screen</strong> is :</p> <pre><code>[info] play - datasource [jdbc:h2:mem:play] bound to JNDI as DefaultDS [info] play - database [default] connected at jdbc:h2:mem:play [info] play - Application started (Dev) [error] o.h.u.JDBCExceptionReporter - Table "USERD" not found; SQL statement: insert into Userd (email, name, password, empid) values (?, ?, ?, ?) [42102-168] [error] application - ! @6fiph0k4b - Internal server error, for (POST) [/login] -&gt; play.api.Application$$anon$1: Execution exception[[RollbackException: Error while committing the transaction]] at play.api.Application$class.handleError(Application.scala:289) ~[play_2.10.jar:2.1.2] at play.api.DefaultApplication.handleError(Application.scala:383) ~[play_2.10.jar:2.1.2] at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$play$core$server$netty$PlayDefaultUpstreamHandler$$handle$1$1.apply(PlayDefaultUpstreamHandler.scala:143) ~[play_2.10.jar:2.1.2] at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$play$core$server$netty$PlayDefaultUpstreamHandler$$handle$1$1.apply(PlayDefaultUpstreamHandler.scala:139) ~[play_2.10.jar:2.1.2] at play.api.libs.concurrent.PlayPromise$$anonfun$extend1$1.apply(Promise.scala:113) ~[play_2.10.jar:2.1.2] at play.api.libs.concurrent.PlayPromise$$anonfun$extend1$1.apply(Promise.scala:113) ~[play_2.10.jar:2.1.2] javax.persistence.RollbackException: Error while committing the transaction at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:93) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final] at play.db.jpa.JPA.withTransaction(JPA.java:107) ~[play-java-jpa_2.10.jar:2.1.2] at play.db.jpa.TransactionalAction.call(TransactionalAction.java:14) ~[play-java-jpa_2.10.jar:2.1.2] at play.core.j.JavaAction$$anon$2.apply(JavaAction.scala:80) ~[play_2.10.jar:2.1.2] at play.core.j.JavaAction$$anon$2.apply(JavaAction.scala:79) ~[play_2.10.jar:2.1.2] at play.libs.F$Promise$PromiseActor.onReceive(F.java:425) ~[play_2.10.jar:2.1.2] Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not insert: [models.Userd] at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1315) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:81) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final] at play.db.jpa.JPA.withTransaction(JPA.java:107) ~[play-java-jpa_2.10.jar:2.1.2] at play.db.jpa.TransactionalAction.call(TransactionalAction.java:14) ~[play-java-jpa_2.10.jar:2.1.2] at play.core.j.JavaAction$$anon$2.apply(JavaAction.scala:80) ~[play_2.10.jar:2.1.2] Caused by: org.hibernate.exception.SQLGrammarException: could not insert: [models.Userd] at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:92) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2454) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2874) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.action.EntityInsertAction.execute(EntityInsertAction.java:79) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final] at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:273) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final] Caused by: org.h2.jdbc.JdbcSQLException: Table "USERD" not found; SQL statement: insert into Userd (email, name, password, empid) values (?, ?, ?, ?) [42102-168] at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) ~[h2.jar:1.3.168] at org.h2.message.DbException.get(DbException.java:169) ~[h2.jar:1.3.168] at org.h2.message.DbException.get(DbException.java:146) ~[h2.jar:1.3.168] at org.h2.command.Parser.readTableOrView(Parser.java:4770) ~[h2.jar:1.3.168] at org.h2.command.Parser.readTableOrView(Parser.java:4748) ~[h2.jar:1.3.168] at org.h2.command.Parser.parseInsert(Parser.java:958) ~[h2.jar:1.3.168] </code></pre> <p>can any one please give me idea to fix this issue and <strong>is it necessary to create sql file before run the app</strong> </p> <p>give some idea!</p> <p><strong>persistence.xml</strong></p> <pre><code>&lt;persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd" version="2.0"&gt; &lt;persistence-unit name="defaultPersistenceUnit" transaction-type="RESOURCE_LOCAL"&gt; &lt;provider&gt;org.hibernate.ejb.HibernatePersistence&lt;/provider&gt; &lt;non-jta-data-source&gt;DefaultDS&lt;/non-jta-data-source&gt; &lt;properties&gt; &lt;property name="hibernate.dialect" value="org.hibernate.dialect.H2Dialect"/&gt; &lt;property name="hibernate.hbm2ddl.auto" value="update"/&gt; &lt;/properties&gt; &lt;/persistence-unit&gt; &lt;/persistence&gt; </code></pre> <p><strong>application.conf</strong>: u can see on this link:</p> <p><a href="http://shorttext.com/Zw96Q" rel="nofollow">application.conf</a></p> <p>it is creating database but it is not creating evolution file in project.</p>
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    1. USRahul Kulhari
    1. USRahul Kulhari
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