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    <pre><code>public class UniqueNumbers { public static void main(String[] args) { args = new String[6]; args[0] = "5"; args[1] = "6"; args[2] = "2"; args[3] = "5"; args[4] = "1"; args[5] = "1"; Arrays.sort(args); // Sort the array. This will use natural order: // low -&gt; high for integers, a -&gt; z and low to high for strings // Essentially this causes our array to sort from low to high, despite not being integers for (int i = 0; i &lt; args.length; i++) { // Loop over the entire array if (i == 0) { // (1) System.out.println(args[0]); } else if (!(args[i - 1].equals(args[i]))) { // (2) System.out.println(args[i]); } } } } </code></pre> <p>Output:</p> <pre><code>1 2 5 6 </code></pre> <p>Clarification:</p> <p>To make it easy to demonstrate, I've manually placed the values into the array. This makes no difference, you can just keep using your input method.</p> <p>(1): Read <code>(2)</code> first. Because of the method below, we would essentially skip the first element. The second part of the <code>else if</code> essentially means <code>if i &gt; 0</code>. If we wouldn't do this, we would get an <code>ArrayIndexOutOfBoundsException</code> when we do <code>args[i - 1]</code> because that would try to access <code>args[-1]</code>. That's why we skip the first element: to avoid this. However, this would also mean that our first value (<code>1</code>) would be ignored. That's why we just want to make sure the first value is always printed.</p> <p>(2): Now we check if the current element (<code>args[i]</code>) is equal (<code>.equals()</code>) to the previous elements (<code>args[i -1]</code>). If this is not the case (<code>!</code> inverts a statement), we print the current value.</p> <p>With this method, you can solve your assignment without any datastructures apart from the the standard one. </p> <p>More visualization:</p> <p>Start:</p> <pre><code>5 6 2 5 1 1 </code></pre> <p>Sort:</p> <pre><code>1 1 2 5 5 6 </code></pre> <p>Loop:</p> <pre><code>! 1 1 2 5 5 6 -&gt; Output: 1 ! 1 1 2 5 5 6 -&gt; Not different from previous one, no output ! 1 1 2 5 5 6 -&gt; Different from previous one, output: 1 2 ! 1 1 2 5 5 6 -&gt; Different from previous one, output 1 2 5 ! 1 1 2 5 5 6 -&gt; Not different from previous one, no output ! 1 1 2 5 5 6 -&gt; Different from previous one, output 1 2 5 6 </code></pre>
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    1. POHow do I get Java to output unique integers from a command-line argument?
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    1. USJeroen Vannevel
    1. USJeroen Vannevel
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    1. POHow do I get Java to output unique integers from a command-line argument?
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    1. COThis is great. Thanks! What if I had to do this without sorting? :)
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      1. USstburnish
    2. CO@stburnish: Create a function that loops trough your array, gets the min value, stores it in a temp variable and prints it out. Then remove it from the array and do the same again. If the new minimum is the same as the temp variable, don't print it. Do this untill your array is empty. I'm not going to write this out though; the above solution entirely fits your requirements. You cannot solve this without using at least the `args` array.
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      1. USJeroen Vannevel
 

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