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    <pre><code>public static double toDouble(String a){ int sign = 1; int start = 0; if(a.charAt(0) == '-'){ start = 1; sign = -1; } double value = 0; boolean decimal = false; int exp = 0; for(int i = start; i &lt; a.length(); i++){ if(a.charAt(i) == '.'){ if(decimal) return 0.0; decimal = true; }else{ value += (a.charAt(i) - 48) * Math.pow(10,a.length() - i - 1); } if(decimal) exp++; } value = value / Math.pow(10,exp); value *= sign; System.out.println(value); return value; } </code></pre> <p>I sort of rewrote it the way i would do this problem. If you remember i posted psuedo code on your other question this is my "programmed" version. </p> <p>This is how my code works.</p> <p>First it checks the sign at the first character <code>[0]</code> then increments the <code>start</code> position to 1 instead of zero to start the loop past the <code>-</code> sign. </p> <p>It loops through the array and checks to see if there is a <code>.</code> if it is it sets the decimal variable to true instead of false. If it reads more than one decimal point in the string it will return a <code>0.0</code> which i denoted as a fail value. However, if it doesn't pick up anymore decimals it increments the exponent value to see how many spaces it will need to jump.</p> <pre><code>value += (a.charAt(i) - 48) * Math.pow(10,a.length() - i - 1); </code></pre> <p>this line of code is very interesting. <code>a.charAt(i) - 48</code> converts the character to an integer value. then i multiply it by 10^(what power of ten the value is at then subtract one to compensate for <code>1.0</code>). Then i add it value.</p> <p>Everything else is pretty self explanatory. </p> <p><strong>NOTE:</strong></p> <p>I tested this code myself, however one important thing is that i haven't added checks for invalid strings with other characters. </p>
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    1. COmay i know the use of this statement `if(decimal) return 0.0`?
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    2. CO@BlackPanther It's a error check essentially. If it detects more than one `.` it would be an invalid string `3.333.3` is not a decimal so it returns a `null` in this case i represented it as `0.0`
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    3. COoh nice.. :) but if this `int count = a.length() - a.replace(".", "").length();` is implemented and a check is made on count before the for loop, saves time because if `3.333.3` is entered we wouldn't be wasting time by parsing 5 characters unnecessarily :)
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