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    <p>Further to MikeW's excellent but incomplete answer, you need a way to request the time from the server and receive it back in the DOM.</p> <p><strong><em>There is only one way to do that: AJAX.</em></strong></p> <p>As Mike pointed out, the PHP code that you typed above only runs once: when the page is first generated. After the page has been generated and the document is "ready", you must use AJAX.</p> <p>Below is a fully-working, copy/pastable example to demonstrate one way this could work.</p> <p>Note that I had to over-ride the <code>orderedtime</code> variable because I don't know how/when you set that.</p> <p>HTML/javascript side: <strong>index.php</strong></p> <pre><code>&lt;html&gt; &lt;head&gt; &lt;script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"&gt;&lt;/script&gt; &lt;script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.9.1/jquery-ui.min.js"&gt;&lt;/script&gt; &lt;link rel="stylesheet" href="http://code.jquery.com/ui/1.9.1/themes/base/jquery-ui.css" /&gt; &lt;style&gt; #timeDiv{width:40%;height:200px;background:wheat;padding:10px;} &lt;/style&gt; &lt;script type="text/javascript"&gt; $(document).ready(function() { //var orderedtime = "&lt;?php echo $_SESSION['ordertime']; ?&gt;"; var orderedtime = ''; if (orderedtime === null || orderedtime == ''){ console.log("orderedtime is not set"); }else{ doAjax(); } window.setInterval(function(){ doAjax(); },2000); }); //END document.ready function doAjax() { $.ajax({ type: "POST", url: "get_the_time.php", data: "ordertime=" + orderedtime, success: function(myData) { $('#thetime').html(myData); } }); } &lt;/script&gt; &lt;/head&gt; &lt;body&gt; &lt;div id="timeDiv"&gt; The time is: &lt;span id="thetime"&gt;&lt;/span&gt; &lt;/div&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <hr> <p>PHP side: <strong>get_the_time.php</strong></p> <pre><code>&lt;?php if (isset($_POST['ordertime']) != true) { $d = date("h:i:s"); }else{ $ot = $_POST['ordertime']; $d = date('h:i:s', (strtotime($ot) + (1 * 60))); } echo $d; </code></pre> <hr> <p><strong>IMPORTANT NOTE:</strong> </p> <p>When using AJAX, the response sent from the server is received inside the <code>success:</code> function, <strong><em>and no where else.</em></strong></p> <p>If you later wish to use that data, assigning it into a variable inside the success function will not work. The best way I have found is to stick the received data into an element of some kind (a hidden input field works great for this), and then retrieve it from there when needed.</p> <p>For example:</p> <pre><code>&lt;input type="hidden" id="myHiddenField" /&gt; $.ajax({ type: "POST", url: "get_the_time.php", data: "ordertime=" + orderedtime, success: function(myData) { $('#thetime').html(myData); $('#myHiddenField').val(myData); } }); </code></pre> <p>Then, inside some other javascript function, you can grab that data and assign it to some variable, thus:</p> <pre><code>var someVar = $('#myHiddenField').val(); </code></pre> <p>Hope this helps, late as it is.</p> <hr> <p><kbd><a href="https://stackoverflow.com/questions/18724011/post-not-posting-data/18724684#18724684">This stackoverflow post</a></kbd> has further information/explanation regarding AJAX. Check out the simplified AJAX examples at the bottom.</p>
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    1. POHow to update the PHP current timestamp using jquery/javascript every second
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