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    <blockquote> <p>First is that, why is const needed before char? or why is it there?. Also, why is it declaring as a pointer?</p> </blockquote> <p>I'll start by answering your last question first. This is declared as a pointer so the constructor can accept an array of characters. The <code>const</code> is there to indicate that the characters being pointed to are not modified inside this <code>bozo</code> constructor. This is important because your example usage can pass in C-style string literals which typically reside in read-only memory portion of your program. Any attempts to modify such a string literal is undefined behavior.</p> <blockquote> <p>Second, is there any difference between the "primary form" and the "short form?"</p> </blockquote> <p>The first form is creating a temporary <code>Bozo</code> object on the right-hand side and that object is used to initialize <code>bozetta</code> on the left-hand side. Now you might think that an extra copy happens with this form but that isn't the case. The C++ standard is worded in such a way so that it permits the compiler to skip this unnecessary extra copy during construction by <em>eliding</em>. So in practice, you'll find that on all modern C++ compilers you try this on, <code>bozetta</code> will be constructed using the prototype you showed above -- no extra copying happens.</p> <p>The second form explicitly constructs a <code>Bozo</code> object using a <code>Bozo</code> constructor that can accept two string literals as parameters.</p> <p>These two forms have the same behavior assuming that constructor isn't declared <code>explicit</code>.</p> <blockquote> <p>I thought char can only contain a single alphabet, and it's not a char array.</p> </blockquote> <p>That is correct, a <code>char</code> can only hold one byte worth of information. C and C++ doesn't have an actual native string type, not like the type you're use to like in other languages. So a "string" is really just a bunch of <code>chars</code> laid out in a contingent block of memory. Your <code>Bozo</code> constructor above can work with this block by taking a pointer to where that block starts as input.</p> <blockquote> <p>Could I do this with string instead?</p> </blockquote> <p>Yes you can and that is actually the preferred way you should do this by using <code>std::string</code>. The constructor declaration would look like this:</p> <pre><code>Bozo(std::string fname, std::string lname); // or to avoid potential copying of long strings Bozo(const std::string &amp;fname, const std::string &amp;lname); </code></pre>
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