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    <p>This one will work the same in all major RDBMS (including SQL Server and MySql)</p> <p><strong>UPDATED</strong> based on your comments</p> <pre><code>SELECT name, so_no, ( SELECT MAX(so_no) FROM table1 WHERE so_no &lt; t.so_no AND name = t.name ) prev_so_no FROM table1 t WHERE so_no = 'SO-00005' </code></pre> <p><strong>SQL Server:</strong></p> <p><strong>UPDATED</strong> based on your comments</p> <pre><code>SELECT name, MAX(so_no) so_no, CASE WHEN MAX(so_no) = MIN(so_no) THEN NULL ELSE MIN(so_no) END prev_so_no FROM ( SELECT TOP 2 t1.name, t1.so_no FROM table1 t1 JOIN table1 t2 ON t1.name = t2.name WHERE t2.so_no = 'SO-00005' AND t1.so_no &lt;= t2.so_no ORDER BY so_no DESC ) q GROUP BY name </code></pre> <p>if you're using <strong>SQL Server 2012</strong> then you can also utilize analytic function <a href="http://technet.microsoft.com/en-us/library/hh231256.aspx" rel="nofollow"><code>LAG</code></a></p> <pre><code>SELECT name, so_no, prev_so_no FROM ( SELECT name, so_no, LAG(so_no, 1, NULL) OVER (ORDER BY so_no) prev_so_no, ROW_NUMBER() OVER (ORDER BY so_no DESC) rnum FROM table1 WHERE name = 'Adrian' AND so_no &lt;= 'SO-00005' ) q WHERE rnum = 1 </code></pre> <p>or</p> <pre><code>SELECT TOP 1 name, so_no, prev_so_no FROM ( SELECT name, so_no, LAG(so_no, 1, NULL) OVER (ORDER BY so_no) prev_so_no FROM table1 WHERE name = 'Adrian' AND so_no &lt;= 'SO-00005' ) q ORDER BY so_no DESC </code></pre> <p><strong>MySQL:</strong></p> <pre><code>SELECT name,         MAX(so_no) so_no,         CASE WHEN MAX(so_no) = MIN(so_no)              THEN NULL             ELSE MIN(so_no)        END prev_so_no   FROM (   SELECT name, so_no     FROM table1    WHERE name = 'Adrian'      AND so_no &lt;= 'SO-00005'    ORDER BY so_no DESC    LIMIT 2 ) q    GROUP BY name </code></pre> <p>or</p> <pre><code>SELECT name, SUBSTRING_INDEX(so_no, ',', 1) so_no, CASE WHEN SUBSTRING_INDEX(SUBSTRING_INDEX(so_no, ',', 2), ',', -1) = SUBSTRING_INDEX(so_no, ',', 1) THEN NULL ELSE SUBSTRING_INDEX(SUBSTRING_INDEX(so_no, ',', 2), ',', -1) END prev_so_no FROM ( SELECT name, GROUP_CONCAT(so_no ORDER BY so_no DESC) so_no FROM table1 WHERE name = 'Adrian' AND so_no &lt;= 'SO-00005' GROUP BY name ) q </code></pre> <hr> <p>Output for all queries:</p> <pre> | NAME | SO_NO | PREV_SO_NO | |--------|----------|------------| | Adrian | SO-00005 | SO-00002 | </pre> <p>Here is <strong><a href="http://sqlfiddle.com/#!3/45d60/9" rel="nofollow">SQLFiddle</a></strong> demo (<strong>SQL Server 2008</strong>) UPDATED<br> Here is <strong><a href="http://sqlfiddle.com/#!6/45d60/7" rel="nofollow">SQLFiddle</a></strong> demo (<strong>SQL Server 2012</strong>)<br> Here is <strong><a href="http://sqlfiddle.com/#!2/24b19a/18" rel="nofollow">SQLFiddle</a></strong> demo (<strong>MySQL</strong>)</p>
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    1. POHow to get next/previous record number?
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    1. COGood explanation!
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    2. COI'm using MS SQL Server 2008. If there's only one main key "SO No.", can I have the same result? Sorry for my poor English :(
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    3. CO@Amni I updated the topmost example. Here is [SQLFiddle](http://sqlfiddle.com/#!3/45d60/5) for it. Let me know if it works for you.
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