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POAdjust position of a group of adjacent divs in non-linear fashion
 

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  1. POAdjust position of a group of adjacent divs in non-linear fashion
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    <p>This isn't so much a jQuery question as it is an overall conceptual question. In my example I can populate a container with divs that have a top value set in a nonlinear fashion. The top value of each one is calculated based on a formula that takes into account the top position of the one to its left as well as the height of the container (line 33 of fiddle).</p> <pre><code>//this formula sets the top value for each new child added to the container //height is 100% of its parent which is 20% of the body //newOne:last is the most recently added child and will have an initial top value of 10% parseInt($(this).next().css('top'), 10) / $('#queue').height()) * 75 + (parseInt($('.newOne:last').css('top'), 10) * 2) + '%' </code></pre> <p>I more of less stumbled upon this by chance and it seems to work 'ok', but if an optimization is obvious to you, please point it out :) What I'm having trouble coming up with is an elegant formula for how to adjust the children smoothly during a drag event. I'm thinking the top value needs to be adjusted based on some manipulation of the left offset, but after hours of experimenting, I haven't found anything that keeps the original position intact when I start dragging and continues adjusting the values smoothly during my drag. The children should gradually approach a minimum top value of 10% as I drag left (child with left offset of 0 will have a top value of 10%), and gradually move away from that top value back toward their initial position as I drag right. </p> <pre><code>$('#queue').draggable({ axis: "x", scroll: false, drag: function(){ //adjust values of each child $('.newOne').each(function(){ var percentLeft = $(this).offset().left / $('footer').width() * 100 var thisLeft = parseInt($(this).css('left'), 10) / $(window).width() * 100; var thisTop = parseInt($(this).css('top'), 10) / $('#queue').height() * 100; if (percentLeft &gt;= 0){ //top value of each one gradually decreases... //as it gets closer to an offset value of 0 and minimum top value of 10% //non-linear attempt but not even close //$(this).css('top', $(this).css('top', 10 + (thisTop - 10 / thisLeft) + '%')); //linear step $(this).css({'top': 8 + (percentLeft/2) + '%'}); } }); } }); </code></pre> <p><a href="http://jsfiddle.net/5RRCS/17/" rel="nofollow">http://jsfiddle.net/5RRCS/17/</a></p> <p>P.S. I know I'm asking a lot here, but hopefully someone is up to the challenge :)</p> <p><strong>Update:</strong> Stumbled onto exp method and did something like this:</p> <pre><code>adjustTop = function(offset){ return 100 * (1.0-Math.min(0.98,(0.83 + ( 0.17/ (Math.exp(0.007*offset))) )) ) + '%'; }; $(this).css('top', adjustTop($(this).offset().left) ); </code></pre>
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