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    <p><code>char* text = "Hello!"</code> can be thought of as the following:</p> <p>At program start, you create an array of chars, 7 in length: <code>{'H','e','l','l','o','!','\0'}</code>. The last one is the null character and shows that there aren't any more characters after it. [It's more efficient than keeping a count associated with the string... A count would take up perhaps 4 bytes for a 32-bit integer, while the null character is just a single byte, or two bytes if you're using Unicode strings. Plus it's less confusing to have a single array ending in the null character than to have to manage an array of characters and a counting variable at the same time.]</p> <p>The difference between creating an array and making a string constant is that an array is editable and a string constant (or 'string literal') is not. Trying to set a value in a string literal causes problems: they are read-only.</p> <p>Then, whenever you call the statement <code>char* text = "Hello!"</code>, you take the address of that initial array and stick it into the variable <code>text</code>. Note that if you have something like this...</p> <pre><code>char* text1 = "Hello!"; char* text2 = "Hello!"; char* text3 = "Hello!"; </code></pre> <p>...then it's quite possible that you're creating three separate arrays of <code>{'H','e','l','l','o','!','\0'}</code>, so it would be more efficient to do this...</p> <pre><code>char* _text = "Hello!"; char* text1 = _text; char* text2 = _text; char* text3 = _text; </code></pre> <p>Most compilers are smart enough to only initialize one string constant automatically, but some will only do that if you manually turn on certain optimization features.</p> <p>Another note: from my experience, using <code>delete []</code> on a pointer to a string literal doesn't cause issues, but it's unnecessary since as far as I know it doesn't actually delete it.</p>
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    1. POconfusion about char pointer in c++
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    1. CO`"Hello"` in your cases are `string literals` and almost always `read-only` in `data segment`. You will most likely `segfault` if you try to modify them. The only way to "modify" is to make the pointer point to something else.
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    2. COYes but for demonstration purposes it's much like allocating an array.
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    3. COActually I see where I am misleading, let me edit my answer a bit.
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