StackOverflow2013

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2013-09-07T14:08:49.587
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<a href="http://jsfiddle.net/itay1989/J7a5R/10/" rel="noreferrer">jsFiddle Demo</a> <pre><code>div { width: 200px; height: 200px; overflow: hidden; margin: 10px; position: relative; } img { position: absolute; margin: auto; min-height: 100%; min-width: 100%; /* For the following settings we set 100%, but it can be higher if needed See the answer's update */ left: -100%; right: -100%; top: -100%; bottom: -100%; } </code></pre> <hr> <h1>Update - Improvement</h1> As <a href="https://stackoverflow.com/users/87015/salman-a">Salman A</a> mentioned in the comments, the original solution has a flaw - it doesn't work well if the img's height or width (or both) are (at least) 3 times* larger than the containing div. The problem is shown <a href="http://jsfiddle.net/itay1989/J7a5R/768/" rel="noreferrer">here</a>. Salman also gave a really simple and elegant fix. We just need to update the img's position coordinates (top, left, bottom, right) to work with higher percents. The following fix works with 1000%, but of course you can adjust it according to your needs. The fix is shown <a href="http://jsfiddle.net/itay1989/J7a5R/769/" rel="noreferrer">here</a>. <a href="https://i.stack.imgur.com/AQOyv.jpg" rel="noreferrer"><img src="https://i.stack.imgur.com/AQOyv.jpg" alt="Before and after the fix"></a> * The reason is that when we set the img's left and right (or: top and bottom) coordinates to be -100% (of the containing div), the overall allowed width (or: height) of the img, can be at most 300% of the containing div's width (or: height), because it's the sum of the div's width (or: height) and the left and right (or: top and bottom) coordinates.
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