Databases
StackOverflow2013
Postsdbo
POCannot encrypt password in configuration file
 

Note that there are some explanatory texts on larger screens.

plurals
  1. POCannot encrypt password in configuration file
    primarykey
    data
    text
    <p>I'm having trouble encrypting the database password in <code>hibernate.cfg.xml</code></p> <p>This is my property file.</p> <pre class="lang-xml prettyprint-override"><code>&lt;!-- Database connection settings --&gt; &lt;property name="connection.driver_class"&gt;com.microsoft.sqlserver.jdbc.SQLServerDriver&lt;/property&gt; &lt;property name="connection.url"&gt;jdbc:sqlserver://localhost:1433;databaseName=TEST;&lt;/property&gt; &lt;property name="connection.username"&gt;sa&lt;/property&gt; &lt;!-- Encryption --&gt; &lt;property name="connection.password"&gt;ENC(vMO/j5jfpaU2cUhPVoOk5Q==)&lt;/property&gt; &lt;property name="connection.provider_class"&gt;org.jasypt.hibernate4.connectionprovider.EncryptedPasswordDriverManagerConnectionProvider&lt;/property&gt; &lt;property name="connection.encryptor_registered_name"&gt;hibernateEncryptor&lt;/property&gt; </code></pre> <p>Then in the <code>HiberanteUtil.java</code> I have this</p> <pre><code>// Builds session factory. private static SessionFactory configureSessionFactory() throws HibernateException { Configuration configuration = new Configuration().configure(); StandardPBEStringEncryptor encryptor = new StandardPBEStringEncryptor(); encryptor.setPassword("pass"); HibernatePBEEncryptorRegistry registry = HibernatePBEEncryptorRegistry.getInstance(); registry.registerPBEStringEncryptor("hibernateEncryptor", encryptor); ServiceRegistry serviceRegistry = new ServiceRegistryBuilder() .applySettings(configuration.getProperties()).buildServiceRegistry(); return configuration.buildSessionFactory(serviceRegistry); } </code></pre> <p>I've created the encrypted password with <code>encrypt.bat</code>.</p> <p>Then the error i have is </p> <blockquote> <p>com.microsoft.sqlserver.jdbc.SQLServerException: Login failed for user 'sa'. ClientConnectionId:8033573f-5f52-4fe9-a728-fbe4f57d89c4</p> </blockquote> <p>If I remove this part</p> <pre><code>StandardPBEStringEncryptor encryptor = new StandardPBEStringEncryptor(); encryptor.setPassword("someKey"); HibernatePBEEncryptorRegistry registry = HibernatePBEEncryptorRegistry.getInstance(); registry.registerPBEStringEncryptor( "hibernateEncryptor", encryptor); </code></pre> <p>I have the same error, so I think it doesn't register but I have no idea how to do it.</p> <p>This is how i encrypt</p> <p><img src="https://i.stack.imgur.com/F9Fhw.png" alt="jasypt problem image"></p> <p><strong>UPDATE</strong></p> <p>The only thing i can made to get it work is something like this, but is not the way i think. </p> <pre><code>StandardPBEStringEncryptor encryptor = new StandardPBEStringEncryptor(); encryptor.setPassword("somePass"); encryptor.setAlgorithm("PBEWITHMD5ANDDES"); String pass=encryptor.decrypt("HhpmA/XmJoLro8TYYu4YyA=="); HibernatePBEEncryptorRegistry registry = HibernatePBEEncryptorRegistry.getInstance(); registry.registerPBEStringEncryptor( "hibernateEncryptor", encryptor); Configuration configuration = new Configuration().configure() .setProperty("hibernate.connection.encryptor_registered_name","hibernateEncryptor") .setProperty("hibernate.connection.password",pass); </code></pre> <p>So i think the problem is with the <code>"hibernateEncryptor"</code>, i think i need to register </p> <pre><code> &lt;typedef name="encryptedString" class="org.jasypt.hibernate4.type.EncryptedStringType"&gt; &lt;param name="encryptorRegisteredName"&gt;hibernateEncryptor&lt;/param&gt; &lt;typedef&gt; </code></pre> <p>But when i put it in <code>hibernate.cfg.xml</code> says invalid mapping, so i add it to a class with annotation but nothing happen cause i think this is read after database connection that is what i want to encrypt. :(</p> <pre><code>@TypeDef(name="encryptedString",typeClass=org.jasypt.hibernate4.type.EncryptedStringType.class, parameters= {@Parameter(name="encryptorRegisteredName",value="hibernateEncryptor")}) </code></pre>
    singulars
    1. PO
      singulars
      1. PTAnswer
    1. This table or related slice is empty.
    1. PTQuestion
    1. USnachokk
    1. USnachokk
    plurals
    1. PL
      singulars
      1. LTLinked
    1. This table or related slice is empty.
    1. This table or related slice is empty.
    1. PO
      singulars
      1. PTAnswer
    2. PO
      singulars
      1. PTAnswer
    3. PO
      singulars
      1. PTAnswer
    1. VO
      singulars
      1. POCannot encrypt password in configuration file
      1. This table or related slice is empty.
      1. VTUpMod
    2. VO
      singulars
      1. POCannot encrypt password in configuration file
      1. USnachokk
      1. VTBountyStart
    3. VO
      singulars
      1. POCannot encrypt password in configuration file
      1. This table or related slice is empty.
      1. VTUpMod
    1. COCan you specify Hibernate version and Jasypt version?
      singulars
      1. POCannot encrypt password in configuration file
      1. USHaim Raman
    2. CO@Haim `hibernate-4.1` and `jasypt 1.9.1` `jasypt-hibernate4-1.91`
      singulars
      1. POCannot encrypt password in configuration file
      1. USnachokk
 

Querying!

 
Guidance
A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

SQuiL has stopped working due to an internal error.

If you are curious you may find further information in the browser console, which is accessible through the devtools (F12).

Reload