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POWhy won't this tic-tac-toe code execute?
 

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  1. POWhy won't this tic-tac-toe code execute?
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    <p>I'm trying to learn python and have been writing a (very) simple tic-tac-toe program. However, I've got stuck because it won't seem to execute beyond letting the user enter a number. After that, nothing happens. I can't figure out where I have gone wrong. Sure there are tons of errors, but help much appreciated!</p> <p>Thanks!</p> <pre><code>import random board = range(0,9) def print_board(): print board[0], "|", board[1], "|", board[2] print board[3], "|", board[4], "|", board[5] print board[6], "|", board[7], "|", board[8] def checkAll(): if board[0] == board[1] == board[2]: True if board[3] == board[4] == board[5]: True if board[6] == board[7] == board[8]: True if board[0] == board[3] == board[6]: True if board[1] == board[4] == board[7]: True if board[2] == board[5] == board[8]: True if board[0] == board[4] == board[8]: True if board[6] == board[4] == board[2]: True print_board() while True: input = int(raw_input("Choose a number to place your X: ")) if input &lt;= 8: if board[input] != "x" or board[input] != "o": board[input] = "x" # places x if board[input] is neither x or o # Check for winner if checkAll() == True: "The game is over!" break; finding = True while finding: random.seed() # gives a random generator opponent = random.randrange(0,8) # generates a random integer between 1 and 8 if board[opponent] != "x" or board[opponent] != "o": board[opponent] = "o" # Check for winner if checkAll() == True: "The game is over!" break; else: print "This spot is taken." print_board() else: "Please choose a number between O and 8." </code></pre>
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    1. USKay Cee
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    1. COWhat do you expect `if board[0] == board[1] == board[2]: True` to do?
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      1. USTerryA
    2. COYes, True is a Bool its not going to do anything
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    3. COFirst off, as pointed out by @Haidro, you would need to `return True`
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      1. USsberry
 

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