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POConverting roman numerals into numbers using find statement in C++
 

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  1. POConverting roman numerals into numbers using find statement in C++
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    <p>Hi I am having trouble converting roman numerals into normal numbers in C++, the code works to a degree however it if the numerals (XIV 14 or LIV etc) are entered it will out put 15 or 55. I have tried to implement the find statement however I have no real idea how to use it to solve my problem, here is a copy of my code so far;</p> <pre><code>int convNum; int total = 0; string romanNum; const string units [10]= {"0","I","II","III","IV","V","VI","VII","VIII","IX"}; const string tens [10]= {"0","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"}; const string hundreds [10]= {"0","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"}; const string thousands [4]= {"0","M","MM","MMM"}; string input; while(!cin.eof()){ cin&gt;&gt;romanNum; if(cin.fail()){ break; }else{ for(int i=0; i&lt;romanNum.length(); i++){ romanNum[i]=toupper(romanNum[i]); } for(int y=3; y &gt; 0; y--){ if(romanNum.find(thousands[y])!= string::npos){ total += y*1000; input.erase(0,thousands[y].length()); break; } } for(int y=9; y &gt; 0; y--){ if(romanNum.find(hundreds[y])!= string::npos){ total += y*100; input.erase(0,hundreds[y].length()); break; } } for(int y=9; y &gt; 0; y--){ if(romanNum.find(tens[y])!= string::npos){ total += y*10; input.erase(0,tens[y].length()); break; } } for(int y=9; y &gt; 0; y--){ if(romanNum.find(units[y])!= string::npos){ total += y; input.erase(0,units[y].length()); break; } } cout &lt;&lt; total &lt;&lt; endl; total = 0; } for(int k=0; k &lt; romanNum.length(); k++){ input[k] = romanNum[k]; } } return 0; </code></pre> <p>}</p> <p>If anyone can help me with this it will be greatly appreciated, as I am a beginner and coding this amount of C++ code took me around 2 weeks to code.</p>
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    1. USBrenton
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    1. COWoah, 2 weeks?! :O
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      1. USDoorknob
    2. COAre you allowed to implement this using a different technique? For me, the first one that comes to mind is a state machine.
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      1. USChris Jester-Young
    3. CONo I don't think so, (sorry I have no idea what state machine even is)
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