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PO
 

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  1. PO
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    <p>It's a bit verbose, but I think this is probably the most efficient way to do it (unless someone can come up with a clever way to check both diagonals at once).</p> <pre><code>public class TicTacToe { char[][] ticTacToe = {{'X',' ','O'}, {'O','X','O'}, {'X',' ','X'},}; private Character winner = null; public Character getWinner() { return this.winner; } public boolean isSolved() { this.checkSolved(); return this.winner != null; } private void checkSolved() { for(int i = 0; i &lt; ticTacToe.length; i++) { Character win = checkRow(i); if(win != null || (win = checkColumn(i)) != null) { this.winner = win; return; } } //Check diagonal top left to bottom right if(this.ticTacToe[0][0] != ' ') { if(this.ticTacToe[0][0] == this.ticTacToe[1][1] &amp;&amp; this.ticTacToe[1][1] == this.ticTacToe[2][2]) { this.winner = this.ticTacToe[0][0]; } } //Check diagonal top right to bottom left else if(this.ticTacToe[0][2] != ' ') { if(this.ticTacToe[0][2] == this.ticTacToe[1][1] &amp;&amp; this.ticTacToe[1][1] == this.ticTacToe[2][0]) { this.winner = this.ticTacToe[0][2]; } } } private Character checkRow(int row) { if(this.ticTacToe[row][0] == ' ') { return null; } if(this.ticTacToe[row][0] == this.ticTacToe[row][1] &amp;&amp; this.ticTacToe[row][1] == this.ticTacToe[row][2]) { return this.ticTacToe[row][0]; } return null; } private Character checkColumn(int column) { if(this.ticTacToe[0][column] == ' ') { return null; } if(this.ticTacToe[0][column] == this.ticTacToe[1][column] &amp;&amp; this.ticTacToe[1][column] == this.ticTacToe[2][column]) { return this.ticTacToe[column][0]; } return null; } public static void main(String[] args) { TicTacToe ttt = new TicTacToe(); if(ttt.isSolved()) { System.out.println(ttt.getWinner()); // X } } } </code></pre>
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    1. POtesting tic tac toe win condition
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    1. COgee wiz. that is a pretty compact way of doing things. Thanks!
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