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POC++ alphabet equivalent digit code output program
 

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  1. POC++ alphabet equivalent digit code output program
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    <p><code>I have actually this code for an embedded application. I am 1st trying to make it for plain c++ so that I may have concept clear</code>.</p> <p>I have a digit code assigned to each English alphabet. I want that my program outputs equivalent digit code for a sentence. A loop actually should iterate number of times for each digit of the code for sentence. Bec I need to ON/OFF pins for me embedded application for each digit. I have to add time difference between digits of same letter, between two letters, &amp; between two sentences later. 1st I wanted plain output for each digit of resultant code.</p> <p>Here is my code. I have assigned alphabets to String &amp; code to a String array type. Then I search for equivalent digit code of character from String array &amp; save it in string type. Now I am wanting to assign each digit from string to int &amp; loop for it. But I am having trouble in assigning string value to int. I have not much experience of C++ programming.</p> <p><strong>EDIT</strong> I have trouble in converting string to int at 1st place, &amp; overall does this logic for solving my problem seems fine. </p> <p>Here is my code, this is how I am trying to solve my problem. </p> <pre><code> #include &lt;iostream&gt; #include &lt;string&gt; using namespace std; string texttopattern(char c) { //Hello world again //125-15-123-123-135 1346-135-1235-123-145 1-1245-1-24-1345 string alphabet = "abcdefghijklmnopqrstuvwqyz"; //osv string code[] = {"1","12","14","145", "15", "124", "1245", "125", "24", "245", "13", "123", "134", "1345", "135", "1234", "12345", "1235", "234", "2345", "136", "1236", "1346", "13456", "1356", "12346"}; int index = alphabet.find(c); if(index!=-1) return code[index]; else return " "; } int main() { string ord; getline(cin, ord); string code=""; for(int i=0; i&lt;ord.length(); i++) { code += texttopattern(ord[i]); } for(int i=0; i&lt;code.length(); i++) { int n = code[i]; //assign a single digit value from string to an //int,string2int assign value is problem here !! while(n&gt;0){ //loop for n times &amp; manipulate PIN in each iteration cout&lt;&lt;"loop"; n--; } //cout&lt;&lt;code[i]&lt;&lt;endl; } return 0; } </code></pre>
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    1. COAnd your question is...?
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    2. COSee http://stackoverflow.com/questions/7663709/convert-string-to-int-c
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    3. CO@MatsPetersson: Assigning string to int and checking about my overall logic for solving my whole problem. I edited OP
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