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2009-12-04T03:52:13.663
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<p>This is all that occurs to me. The linked list is really a seperate detail... so maybe it can be refactored out....</p> <pre><code> public function split(onGroup:CellGroup, directionToMoveSplitCells:String):CellGroup { if (!hasIntersection(onGroup)) return this; valr splitCells:Array; var newGroup:CellGroup ; var numberOfCellsToSplit:int; var splitStartIndex:int; var resultingGroupStartIndex:int; if (directionToMoveSplitCells == "RIGHT") { numberOfCellsToSplit = this.endIndex - onGroup.startIndex + 1; splitStartIndex = this.length - numberOfCellsToSplit; splitCells = trimCells(splitStartIndex, numberOfCellsToSplit); resultingGroupStartIndex = onGroup.endIndex + 1; if (splitCells.length > 0) { newGroup = row.createGroup(splitCells, resultingGroupStartIndex); nextGroup=insertGroup(newGroup,this,nextGroup); } } else { numberOfCellsToSplit = onGroup.endIndex - startIndex + 1; splitStartIndex = 0; splitCells = trimCells(splitStartIndex, numberOfCellsToSplit); resultingGroupStartIndex = onGroup.startIndex - splitCells.length; if (splitCells.length > 0) { newGroup = row.createGroup(splitCells, resultingGroupStartIndex); previousGroup=insertGroup(newGroup,previousGroup,this); var newX:int = (onGroup.endIndex + 1) * cellSize.width; x = newX; } } removeArrayOfCellsFromGroup(splitCells); row.joinGroups(); row.updateGroupIndices(); repositionCellsInGroup(); return newGroup; } private function insertGroup(toInsert:CellGroup,prior:CellGroup,next:CellGroup):CellGroup { toInsert.nextGroup = next; toInsert.previousGroup = prior; if (toInsert.nextGroup ) toInsert.nextGroup.previousGroup = toInsert; if (toInsert.previousGroup ) toInsert.previousGroup.nextGroup = toInsert; return toInsert; } </code></pre> <p>My unindenting of splitCells assigment is to indicate that it is the inoly non-conditional line in the block. I looked at doing what Anon proposed but I can't see any way to make the code actually better that way.</p>
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1. PORefactoring a method containing conditional with extremely different code blocks that are the same ;)
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1. USTim Williscroft
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