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    <blockquote> <p>1) All functions must be declared in their function prototype, and later on, in their definition. Why don't we have to declare the main() function in a prototype first?</p> </blockquote> <p>Not true. Simple example:</p> <pre><code>void foo(){} //definition int main() { foo(); return 0; } </code></pre> <p>Only when one function is called but the definition isn't seen yet, a declaration is required. That will never happen to <code>main</code> since it is the starup of the program.</p> <hr> <blockquote> <p>2) Why do we have to use int main() instead of void main()?</p> </blockquote> <p>Because the standard says so. (To be more precise, it's true on a hosted environment, which is usually the case)</p> <blockquote> <p><strong>C99 5.1.2.2.1 <em>Program startup</em></strong></p> <p>The function called at program startup is named <code>main</code>. The implementation declares no prototype for this function. It shall be defined with a return type of <code>int</code> and with no parameters:</p> <pre><code>int main(void) { /* ... */ } </code></pre> <p>or with two parameters (referred to here as <code>argc</code> and <code>argv</code>, though any names may be used, as they are local to the function in which they are declared):</p> <pre><code>int main(int argc, char *argv[]) { /* ... */ } </code></pre> <p>or equivalent; or in some other implementation-defined manner.</p> </blockquote> <hr> <blockquote> <p>3) What does return 0 exactly do in the main() function? What would happen if I wrote a program ending the main() function with return 1, for example?</p> </blockquote> <p>The return value indicates the result of the program. Usually <code>0</code> indicates success while other values indicates different kinds of failure.</p>
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