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    <p>Try this</p> <pre><code>WITH cte AS ( SELECT *,COUNT(1) OVER(PARTITION BY cnt) pt FROM ( SELECT tt.* ,(SELECT COUNT(id) FROM t WHERE data &lt;= 10 AND ID &lt; tt.ID) AS cnt FROM t tt WHERE data &gt; 10 ) t1 ) SELECT id, [when], data FROM cte WHERE pt &gt;= 3 </code></pre> <p><a href="http://www.sqlfiddle.com/#!3/2e5f4/1" rel="nofollow noreferrer"><strong>SQL FIDDLE DEMO</strong></a></p> <p><strong>OUTPUT</strong></p> <pre><code>id when data 2 2013-08-02 00:00:00.000 121 3 2013-08-03 00:00:00.000 132 4 2013-08-04 00:00:00.000 15 6 2013-08-06 00:00:00.000 1435 7 2013-08-07 00:00:00.000 143 8 2013-08-08 00:00:00.000 18 9 2013-08-09 00:00:00.000 19 </code></pre> <p><strong>EDIT</strong></p> <p>First the inner query counts the no of records where data &lt;= 10</p> <pre><code>SELECT tt.* ,(SELECT COUNT(id) FROM t WHERE data &lt;= 10 AND ID &lt; tt.ID) AS cnt FROM t tt </code></pre> <p>output </p> <pre><code>id when data cnt 1 2013-08-01 00:00:00.000 1 1 2 2013-08-02 00:00:00.000 121 1 3 2013-08-03 00:00:00.000 132 1 4 2013-08-04 00:00:00.000 15 1 5 2013-08-05 00:00:00.000 9 2 6 2013-08-06 00:00:00.000 1435 2 7 2013-08-07 00:00:00.000 143 2 8 2013-08-08 00:00:00.000 18 2 9 2013-08-09 00:00:00.000 19 2 10 2013-08-10 00:00:00.000 1 3 11 2013-08-11 00:00:00.000 1234 3 12 2013-08-12 00:00:00.000 124 3 13 2013-08-13 00:00:00.000 6 4 </code></pre> <p>Then we filter the records with data > 10 </p> <pre><code>WHERE data &gt; 10 </code></pre> <p>Now we count the records by partitoning cnt column</p> <pre><code>SELECT *,COUNT(1) OVER(PARTITION BY cnt) pt FROM ( SELECT tt.* ,(SELECT COUNT(id) FROM t WHERE data &lt;= 10 AND ID &lt; tt.ID) AS cnt FROM t tt WHERE data &gt; 10 ) t1 </code></pre> <p>Output</p> <pre><code>id when data cnt pt 2 2013-08-02 00:00:00.000 121 1 3 3 2013-08-03 00:00:00.000 132 1 3 4 2013-08-04 00:00:00.000 15 1 3 6 2013-08-06 00:00:00.000 1435 2 4 7 2013-08-07 00:00:00.000 143 2 4 8 2013-08-08 00:00:00.000 18 2 4 9 2013-08-09 00:00:00.000 19 2 4 11 2013-08-11 00:00:00.000 1234 3 2 12 2013-08-12 00:00:00.000 124 3 2 </code></pre> <p>The above query is put in cte just like temp table</p> <p>Now select the records that are having the consecutive count >= 3</p> <pre><code>SELECT id, [when], data FROM cte WHERE pt &gt;= 3 </code></pre> <p><strong>ANOTHER SOLUTION</strong></p> <pre><code>;WITH partitioned AS ( SELECT *, id - ROW_NUMBER() OVER (ORDER BY id) AS grp FROM t WHERE data &gt; 10 ), counted AS ( SELECT *, COUNT(*) OVER (PARTITION BY grp) AS cnt FROM partitioned ) SELECT id, [when], data FROM counted WHERE cnt &gt;= 3 </code></pre> <p><a href="https://dba.stackexchange.com/questions/36943/find-n-consecutive-free-numbers-from-table"><strong>Reference URL</strong></a></p> <p><a href="http://www.sqlfiddle.com/#!3/2e5f4/8" rel="nofollow noreferrer"><strong>SQL FIDDLE DEMO</strong></a></p>
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