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POShow phpmyadmin cell in html textbox value
 

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    <p>I have a database in phpmyadmin called <code>fleet hire motors</code>, and in that database is a table called <code>customer</code>. </p> <p>In that table are columns called <code>customerID</code> and <code>Surname</code>. I have already done some coding on one page that lets the user select the <code>customerID</code> to edit the <code>Surname</code>. </p> <p>On the next page I want a textbox. in that textbox, the default value should be what the current <code>Surname</code> is. </p> <p>So, if i was to edit customer with <code>customerID</code> 1 (of which surname is currently <code>Brown</code> and I want to change to <code>Green</code>) the second page would show <code>Surname: [Brown]</code>, where [] encloses a textbox. </p> <p>I currently do not have any code, and would like to keep it primarily php. The first page is called <code>editcustomer.php</code>, and the second is called <code>editcustomer2.php</code>. </p> <p>Any help is appreciated.</p> <p>My current code is:</p> <pre><code>&lt;html&gt; &lt;head&gt; &lt;title&gt;Edit Customer&lt;/title&gt; &lt;/head&gt;&lt;body&gt; &lt;?php mysql_connect("localhost","username","password") or die(mysql_error()); mysql_select_db("fleet hire motors") or die(mysql_error()); ?&gt; &lt;?php $CustomerID = $_GET["CustomerID"]; $query=mysql_query(" SELECT * FROM customer WHERE CustomerID = '$CustomerID' ") or die(mysql_error()); while ($row = mysql_fetch_array($query)) { b$CustomerID = $row["CustomerID"]; } ?&gt; First Name: &lt;input name="FirstName" type="text" value=" &lt;?php $FirstName = $_GET["CustomerID"]; include 'db.php'; $query=mysql_query(" SELECT FirstName FROM customer WHERE CustomerID = '$CustomerID' ") or die(mysql_error()); ?&gt; "&gt; &lt;br&gt; &lt;input name="submitbtn" type="submit" value="Save"&gt; &lt;input name="resubmitbtn" type="submit" value="Reset"&gt; &lt;/form&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>Sorry for all the edits, as I am new to stackoverflow and just learning how to do it.</p> <p>I have now updated my coding thanks to a response, but it is still not working. My most current coding is:</p> <pre><code>&lt;html&gt; &lt;head&gt; &lt;title&gt;Edit Customer&lt;/title&gt; &lt;/head&gt; &lt;body&gt; &lt;?php mysql_connect("localhost","username","password") or die(mysql_error()); mysql_select_db("fleet hire motors") or die(mysql_error()); ?&gt; &lt;?php $CustomerID = $_GET["CustomerID"]; $query=mysql_query(" SELECT * FROM customer WHERE CustomerID = '$CustomerID' ") or die(mysql_error()); $row = mysql_fetch_array($query); if (!$row || !is_array($row)){ $CustomerID = 0; $CustomerFirstName = ''; } else { $CustomerID = $row["CustomerID"]; $CustomerFirstName = $row['FirstName']; } ?&gt; First Name: &lt;input name="FirstName" type="text" value="&lt;?php echo $CustomerFirstName; ? &gt;"&gt; &lt;input name="submitbtn" type="submit" value="Save"&gt; &lt;input name="resubmitbtn" type="submit" value="Reset"&gt; &lt;/form&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>This does not give me anything in the textbox, and my submit button does not work.</p>
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