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  1. PO
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    <p>An exception should be an exception, not the usual program flow. But lets not care about that for now :)</p> <p>The direct answer to you question I believe is no, but you can always work yourself around the problem. I'm posting a small part of some of the ninja stuff I made when implementing unbounded integers (in effect a linked list of integers) which could help you.</p> <p>This is a very simplistic approach for doing checked addition manually if performance is not an issue. Is quite nice if you can overload the operators of the types, ie you control the types.</p> <pre><code>public static int SafeAdd(int left, int right) { if (left == 0 || right == 0 || left &lt; 0 &amp;&amp; right &gt; 0 || right &lt; 0 &amp;&amp; left &gt; 0) // One is 0 or they are both on different sides of 0 return left + right; else if (right &gt; 0 &amp;&amp; left &gt; 0 &amp;&amp; int.MaxValue - right &gt; left) // More than 0 and ok return left + right; else if (right &lt; 0 &amp;&amp; left &lt; 0 &amp;&amp; int.MinValue - right &lt; left) // Less than 0 and ok return left + right; else throw new OverflowException(); } </code></pre> <p>Example with your own types:</p> <pre><code>public struct MyNumber { public MyNumber(int value) { n = value; } public int n; // the value public static MyNumber operator +(MyNumber left, MyNumber right) { if (left == 0 || right == 0 || left &lt; 0 &amp;&amp; right &gt; 0 || right &lt; 0 &amp;&amp; left &gt; 0) // One is 0 or they are both on different sides of 0 return new MyNumber(left.n + right.n); // int addition else if (right &gt; 0 &amp;&amp; left &gt; 0 &amp;&amp; int.MaxValue - right &gt; left) // More than 0 and ok return new MyNumber(left.n + right.n); // int addition else if (right &lt; 0 &amp;&amp; left &lt; 0 &amp;&amp; int.MinValue - right &lt; left) // Less than 0 and ok return new MyNumber(left.n + right.n); // int addition else throw new OverflowException(); } // I'm lazy, you should define your own comparisons really public static implicit operator int(MyNumber number) { return number.n; } } </code></pre> <p>As I stated earlier, you will lose performance, but gain the exceptions.</p>
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    1. USflindeberg
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    1. COMaybe I'm missing something obvious here, but I fail to see what `SafeAdd` does that isn't done with `checked(left+right)`.. You still throw when it overflows, but instead of a single IL instruction, you do dozens of comparisons before coming to the same conclusion & result as `checked()` would
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      1. USIsak Savo
    2. COIn that sense it is useless, but he wanted to be able to pass an action as a function argument which still throws the exception.
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