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    <p>Use references for <code>a</code> and <code>b</code>.</p> <pre><code>void getvals(int &amp;a, int &amp;b) { cout &lt;&lt; "input value a "; cin &gt;&gt; a; cout &lt;&lt; "input value b "; cin &gt;&gt; b; } </code></pre> <p>This declares <code>getvals()</code> to take two reference parameters. Modification to the reference of an object modifies the object that was passed in to the function call.</p> <p>Without the reference, the parameter is passed by value, which creates a copy of the object passed to the function. Then, modifications made to the parameter in the function only affect the copy.</p> <p>Alternatively, you can use <code>std::pair&lt;int, int&gt;</code> to return two integer values from your function (it won't need <em>out-parameters</em> then). You can manually unpack the <code>first</code> and <code>second</code> members into your variables <code>x</code> and <code>y</code>, or you can implement a helper class to do that for you. For example:</p> <pre><code>std::pair&lt;int, int&gt; getvals () { std::pair&lt;int, int&gt; p; std::cin &gt;&gt; p.first; std::cin &gt;&gt; p.second; return p; } template &lt;typename T, typename U&gt; struct std_pair_receiver { T &amp;first; U &amp;second; std_pair_receiver (T &amp;a, U &amp;b) : first(a), second(b) {} std::pair&lt;T, U&gt; operator = (std::pair&lt;T, U&gt; p) { first = p.first; second = p.second; return p; } }; template &lt;typename T, typename U&gt; std_pair_receiver&lt;T, U&gt; receive_pair (T &amp;a, U &amp;b) { return std_pair_receiver&lt;T, U&gt;(a, b); } int main () { int x, y; receive_pair(x, y) = getvals(); //... } </code></pre> <p>If you have C++11 available to you, you can use the more general <code>tuple</code> and the <code>tie</code> helper to do this similarly in a more clean way. This is illustrated in Benjamin Lindley's answer.</p>
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    1. CO@Giswin you posted your answer so soon after jxh that I doubt anybody could accuse you of copying. I posted the same too. It happens sometimes, when there's an obvious solution. You don't need to delete your answer.
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    2. COThank you, I had a feeling that pointers were going to come into it.
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    3. COYou are very welcome. Please note [there are significant differences between pointers and references](http://stackoverflow.com/a/57492/315052).
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