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POUpdating a table with a groupwise maximum MYSQL?
 

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  1. POUpdating a table with a groupwise maximum MYSQL?
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    <p>I had a table with duplicate user_ids with a many to 1 relationship with tasks and payment.</p> <p>I used a groupwise maximum on tasks to return the rows that had the highest task completion percentage. However I would like to update this new table with the highest payment completion stats from the same table.</p> <p>For example:</p> <pre><code>id date taskid payid task_completion pay_value 4722 2007-11-08 16:20:14 2 3 7.14 0 4722 2007-11-08 16:20:14 3 3 0.00 0 4722 2007-11-08 16:20:14 5 3 0.00 0 4722 2007-11-08 16:20:14 2 6 7.14 40 4722 2007-11-08 16:20:14 3 6 0.00 40 4722 2007-11-08 16:20:14 5 6 0.00 40 4724 2007-11-20 15:32:40 4 7 25.71 105 4726 2008-01-28 11:44:50 7 8 7.14 52 4726 2008-01-28 11:44:50 8 8 34.29 52 4726 2008-01-28 11:44:50 10 8 65.71 52 4726 2008-01-28 11:44:50 7 9 7.14 24 4726 2008-01-28 11:44:50 8 9 34.29 24 </code></pre> <p>So I have used a groupwise maximum on task completion to create a new table (with unique id) as follows:</p> <pre><code>id date taskid payid task_completion pay_value 4722 2007-11-08 16:20:14 2 3 7.14 0 4724 2007-11-20 15:32:40 4 7 25.71 105 4726 2008-01-28 11:44:50 10 8 65.71 52 </code></pre> <p>The problem is that for id 4722 the highest pay_value and payid have not been inserted into the resulting table.</p> <p>I would like to update this in the form (using this select):</p> <pre><code>SELECT s1.payid, s1.pay_value, FROM f_tbl s1 LEFT JOIN f_tbl s2 ON s1.cashid = s2.cashid AND s1.pay_value &gt; s2.pay_value WHERE s2.cash_id IS NULL GROUP BY user_id; </code></pre> <p>However it seems that updating the final table based on this query is not possible. I am stumped, thank you for your assistance.</p>
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    1. USMark
    1. USsurfer190
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    1. COYour query selects the minimum pay_value per cashid (so the result you're getting shouldn't be 52 for 4726, but 24) `s1.pay_value > s2.pay_value` should probably be `s1.pay_value < s2.pay_value`
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      1. USJoachim Isaksson
 

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