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POHow can I translate this XPath expression to BeautifulSoup?
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In answer to a <a href="https://stackoverflow.com/questions/1813921/how-to-search-a-html-page-for-an-item-in-a-given-list/1814616#1814616">previous question</a>, several people suggested that I use <a href="http://www.crummy.com/software/BeautifulSoup/" rel="nofollow noreferrer">BeautifulSoup</a> for my project. I've been struggling with their documentation and I just cannot parse it. Can somebody point me to the section where I should be able to translate this expression to a BeautifulSoup expression? <pre><code>hxs.select('//td[@class="altRow"][2]/a/@href').re('/.a\w+') </code></pre> The above expression is from <a href="http://scrapy.org/" rel="nofollow noreferrer">Scrapy</a>. I'm trying to apply the regex <code>re('\.a\w+')</code> to <code>td class altRow</code> to get the links from there. I would also appreciate pointers to any other tutorials or documentation. I couldn't find any. Thanks for your help. Edit: I am looking at this <a href="http://www.whitecase.com/Attorneys/List.aspx?LastName=&FirstName=" rel="nofollow noreferrer">page</a>: <pre><code>>>> soup.head.title <title>White & Case LLP - Lawyers</title> >>> soup.find(href=re.compile("/cabel")) >>> soup.find(href=re.compile("/diversity")) <a href="/diversity/committee">Committee</a> </code></pre> Yet, if you look at the page source <code>"/cabel"</code> is there: <pre><code> <td class="altRow" valign="middle" width="34%"> <a href='/cabel'>Abel, Christian</a> </code></pre> For some reason, search results are not visible to BeautifulSoup, but they are visible to XPath because <code>hxs.select('//td[@class="altRow"][2]/a/@href').re('/.a\w+')</code> catches "/cabel" Edit: cobbal: It is still not working. But when I search this: <pre><code>>>>soup.findAll(href=re.compile(r'/.a\w+')) [<link href="/FCWSite/Include/styles/main.css" rel="stylesheet" type="text/css" />, <link rel="shortcut icon" type="image/ico" href="/FCWSite/Include/main_favicon.ico" />, <a href="/careers/northamerica">North America</a>, <a href="/careers/middleeastafrica">Middle East Africa</a>, <a href="/careers/europe">Europe</a>, <a href="/careers/latinamerica">Latin America</a>, <a href="/careers/asia">Asia</a>, <a href="/diversity/manager">Diversity Director</a>] >>> </code></pre> it returns all the links with second character "a" but not the lawyer names. So for some reason those links (such as "/cabel") are not visible to BeautifulSoup. I don't understand why.
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<python><xpath><beautifulsoup>
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How can I translate this XPath expression to BeautifulSoup?
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1. COHave you tried double-quotes instead of single-quotes: `<a href="/cabel">...</a>`.
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2. COas far as I can tell, BeautifulSoup isn't parsing the page correctly, soup.contents gives nothing after the tag `<a href="https://www.whitecasealumni.com/jsp/Front/login.jsp" target="_blank">` which is towards the beginning of the document.
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