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POhow to read back a char as an int in c
 

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  1. POhow to read back a char as an int in c
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    <p>I am scrolling through a file of characters and saving its data into an array. the file looks like this: <a href="http://pastebin.com/dx4HetT0" rel="nofollow">http://pastebin.com/dx4HetT0</a></p> <p>I've deleted the header information so it's literally a text file with numbers in it. I want to convert these char numbers into bytes in my program so I can do some conversion maths on them.</p> <p>My code is as follows:</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;stdlib.h&gt; #include "../DataProcessing/include/packet.h" int main ( int argc, char *argv[] ) { /* // We assume argv[1] is a filename to open FILE *file = fopen( argv[1], "r" ); */ FILE *file = fopen("C:\\log_hex.txt", "r"); /* fopen returns 0, the NULL pointer, on failure */ if ( file == 0 ) { printf( "Could not open file\n" ); } else { int x; int count = 0; int byteArray[99999]; /* read one character at a time from file, stopping at EOF, which indicates the end of the file. Note that the idiom of "assign to a variable, check the value" used below works because the assignment statement evaluates to the value assigned. */ while ( ( x = fgetc( file ) ) != EOF ) { byteArray[count] = x; printf( "%c", x ); count++; } fclose( file ); getchar(); } } </code></pre> <p>byteArray gets filled with the characters but not in the way I want - I'm getting a character 0 represented as the numerical value 53, 4 is represented as 52, space is represented as 32.... how can I read the character number, and make that number the char value in my byteArray?</p>
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    1. USdannybeckett
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    1. COYou are looking for `strtol()`.
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    2. COpossible duplicate of [Converting string to integer C](http://stackoverflow.com/questions/7021725/converting-string-to-integer-c)
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    3. CO[Check this question too](http://stackoverflow.com/questions/7787423/c-get-nth-byte-of-integer)
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      1. USSuvarna Pattayil
 

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