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POOutputting a combination of different array values depending on what has been input
 

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    <p>I've created an android app that receives and reads in SMS messages.<br> At the moment the application reads in the SMS and converts it to an array of 8 char's as it will only ever receive messages of 8 characters. for example the message might be "AbCdEfGh" which would be converted to [A][b][C][d][E][f][G][h]. <br></p> <pre><code>if (array[0] == 'a'){ this.abortBroadcast(); Toast.makeText(context, "a", Toast.LENGTH_LONG).show(); context.sendBroadcast(in); } else if (array[0] == 'A'){ //this.abortBroadcast(); //Toast.makeText(context, "A", Toast.LENGTH_LONG).show(); //context.sendBroadcast(in); } else if (array[1] == 'b'){ this.abortBroadcast(); Toast.makeText(context, "b", Toast.LENGTH_LONG).show(); context.sendBroadcast(in); } else if (array[1] == 'B'){ this.abortBroadcast(); Toast.makeText(context, "B", Toast.LENGTH_LONG).show(); context.sendBroadcast(in); } </code></pre> <p>What I want the app to do is read each one of these chars and do something depending on if the character is uppercase or lowercase. For example if [0] equals 'a' then do something, else if [0] equals [A] then do something, and then move on and check the next element.<br><br> I would like it to go through each element of the array and do something for each character in the message, currently the app will show "a" for 'a' and "A" for 'A' perfectly, the problem being that if you enter "ab" it will still only show "a" rather than "ab". it will only show the second letter if you enter the first one as blank, for example " b" will return "b".<br><br> How should i arrange my code so that it selects and shows a combination of the arrays?? surely I do not have to just code each possible combination of the 8 characters that could be involved?? Could a switch statement be the solution? Would it be possible to implement some kind of loop so that once it has looked at the first array element, it loops round and looks at the next element?? Apologies if i have not explained this very clearly! hopefully someone with a bit more experience than me will be able to get their head round this problem. Thanks for any help</p>
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    1. COyou are trying to match two characters at a time with one character, which is not possible, with your code,so when you enter 'ab' at [0] it will match a and will end , when you have " b" will match [1]=='b', are you getting it
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    2. COyes this is correct. i would like it to carry on looking for another letter once it has decided whether [0] is 'A' or 'a'. so does [0] == 'a'? then do this and then carry on and do, does [1] == 'b'? then do this
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    3. COso will i have to tell it what to do for each possible combination of 8 different characters? surely there is a way around this??
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