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    <p>A simple way with <a href="http://docs.python.org/library/re.html?highlight=re.sub#re.subn" rel="nofollow noreferrer">re.subn</a>, which can also accept a function instead of a replacement string:</p> <pre><code>import re from random import randint def select(m): choices = m.group(1).split('|') return choices[randint(0, len(choices)-1)] def spinner(s): r = re.compile('{([^{}]*)}') while True: s, n = r.subn(select, s) if n == 0: break return s.strip() </code></pre> <p>It simply replaces all the deepest choices it meets, then iterates until no choice remains. <code>subn</code> returns a tuple with the result and how many replacements were made, which is convenient to detect the end of the processing.</p> <p>My version of <code>select()</code> can be replaced by Bobince's that uses <code>random.choice()</code> and is more elegant if you just want to stick to a random selector. If you want to build a choice tree, you could extend the above function, but you will need global variables to keep track of where you are, so moving the functions into a class would make sense. This is just a hint, I won't develop that idea since it was not really the orginial question.</p> <p>Note finally that you should use <code>r.subn(select, s, re.U)</code> if you need unicode strings (<code>s = u"{...}"</code>)</p> <p>Example:</p> <pre><code>&gt;&gt;&gt; s = "{{Hello|Hi|Hey} {world|earth} | {Goodbye|farewell} {noobs|n3wbz|n00blets}}" &gt;&gt;&gt; print spinner(s) 'farewell n3wbz' </code></pre> <hr> <p><strong>Edit:</strong> Replaced <code>sub</code> by <code>subn</code> to avoid infinite loop (thanks to Bobince to point it out) and make it more efficient, and replaced <code>{([^{}]+)}</code> by <code>{([^{}]*)}</code> to extract empty curly brackets as well. That should make it more robust to ill-formatted patterns.</p> <p>For people who like to put as much as possible on one line (which I personally wouldn't encourage):</p> <pre><code>def spin(s): while True: s, n = re.subn('{([^{}]*)}', lambda m: random.choice(m.group(1).split("|")), s) if n == 0: break return s.strip() </code></pre>
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    1. POHow to make article spinner regex?
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    1. POHow to make article spinner regex?
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    1. COsnap (almost)! the `{` test would go into an infinite loop if there was an unmatched `{` in the input, though.
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    2. COYou're right, I fixed the code and made the test unnecessary.
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    3. COdoh, and I hadn't spotted subn, either! Well, we've ended up with an acceptable program between us :-)
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