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    <p>Here's one way:</p> <pre><code>regmatches(tt, regexpr("[0-9].*[0-9]", tt)) </code></pre> <p>I assume that there are no other numbers in your file names. So, we just search for start of a number and use the greedy operator <code>.*</code> so that everything until the last number is captured. This is done using <code>regexpr</code> which'll get the position of matches. Then we use <code>regmatches</code> to extract the (sub)string out of these matched positions.</p> <hr> <p>where <code>tt</code> is:</p> <pre><code>tt &lt;- c("Species Count (2011-12-15-07-09-39).xls", "Species Count 0511.xls", "Species Count 151112.xls", "Species Count1011.xls", "Species Count2012-01.xls", "Species Count201207.xls", "Species Count2013-01-15.xls") </code></pre> <hr> <h2>Benchmarking:</h2> <h3>Note: Benchmarking results may differ between Windows and *nix machines (as @Hansi notes below under comments).</h3> <p>Quite some nice answers there. So, it's time for benchmarking :)</p> <pre><code>tt &lt;- rep(tt, 1e5) # tt is from above require(microbenchmark) require(stringr) aa &lt;- function() regmatches(tt, regexpr("[0-9].*[0-9]", tt)) bb &lt;- function() gsub("[A-z \\.\\(\\)]", "", tt) cc &lt;- function() str_extract(tt,'([0-9]|[0-9][-])+') microbenchmark(arun &lt;- aa(), agstudy &lt;- cc(), Jean &lt;- bb(), times=25) Unit: seconds expr min lq median uq max neval arun &lt;- aa() 1.951362 2.064055 2.198644 2.397724 3.236296 25 agstudy &lt;- cc() 2.489993 2.685285 2.991796 3.198133 3.762166 25 Jean &lt;- bb() 7.824638 8.026595 9.145490 9.788539 10.926665 25 identical(arun, agstudy) # TRUE identical(arun, Jean) # TRUE </code></pre>
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    1. POR: extract part of a filename
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    1. COThe OT could also try this regex `([a-zA-Z]:(\\w+)*\\[a-zA-Z0_9]+)?.xls` because all his files are `*.xls`
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    2. COI think your comment should be directed under the OP's question or as a separate answer.
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    3. CO+1 Far more elegant than my solution!
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