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    <p>A few things to fix in your first example:</p> <ol> <li><p>Right now, <code>j &lt; circles[0].length</code> means that only one column is being searched: column <code>0</code>. You'll want <code>j &lt; circles[i].length</code> to search every column by row.</p></li> <li><p><code>if (temp == r)</code> means you're comparing a <code>Circle</code> and a <code>double</code>. I'm not familiar with the circle class, but I believe you'll want to replace instead of <code>Circle temp = circles[i][j]</code> with <code>double temp = circles[i][j].getRadius();</code>.</p></li> <li><p>You want to return as soon as you find the matching <code>Circle</code>, so you have some things a little backwards. With my new revisions, <code>if (temp == r)</code> will now activate the code if you have found the correct radius. That means below that <code>if</code> statement, you'll want <code>return {i, j};</code>. That will return the current circle's (which has the correct radius) indicies.</p></li> <li><p>The last statement will be called if none of the radius tests return true, so where you have <code>return circles.indexOf(r);</code>, you'll want <code>return {-1, -1};</code>.</p></li> <li><p>Since arrays are 0-based, and less than already means one minus the value, you do not need <code>- 1</code> in <code>i &lt; circles.length - 1</code></p></li> </ol> <p>On your second example:</p> <p>Your <code>findCircleWithRadius</code> method has two paramaters: a <code>Circle[][]</code> and a <code>double</code>. That means you'll need to give it those. The method you created is not called from a double, as well, so you can't say <code>r1.findCircleWithRadius();</code> Additionally, you need to use the <code>int[]</code> that the <code>findCircleWithRadius</code> passes you to get those <code>Circle</code>'s. Therefore, your first lines in <code>swapCircles</code> should be:</p> <pre><code>int[] rad1 = this.findCircleWithRadius(circles, r1); // Get the coordinates of the first circle by passing the 2D array, and the radius you're looking for. int[] rad2 = this.findCircleWithRadius(circles, r2); // Get the coordinates of the second circle by passing the 2D array, and the radius you're looking for. Circle radius1 = circles[rad1[0]][rad1[1]]; // Circle 1 is equal to the Circle in the array that has coordinates of the first index in the coordinates, and the second index of the coordinates. (circles[x, y]) Circle radius2 = circles[rad2[0]][rad2[1]]; // Circle 2 is equal to the Circle in the array that has coordinates of the first index in the coordinates, and the second index of the coordinates. (circles[x, y]) </code></pre> <p>In conclusion, the completed code with my revisions will be as follows:</p> <pre><code>public int[] void findCircleWithRadius(Circle[][] circles, double r) { for(int i = 0; i &lt; circles.length; i++) { //search the row for(int j = 0; j &lt; circles[i].length; j++) { //search each column double temp = circles[i][j].getRadius(); if(temp == r) return {i, j}; } } return {-1, -1}; } public static void swapCircles(Circles[][] circles, double r1, double r2) { int[] rad1 = this.findCircleWithRadius(circles, r1); int[] rad2 = this.findCircleWithRadius(circles, r2); Circle radius1 = circles[rad1[0]][rad1[1]]; Circle radius2 = circles[rad2[0]][rad2[1]]; Circle temp2 = radius2; radius2 = radius1; radius1 = temp2; } </code></pre> <p>Otherwise, everything else is looking pretty good! I hope you did well on your quiz! Please let me know if you have any further questions about anything I have said so I can make sure you understand this fully.</p>
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    1. POFind and search for a double in an array and return its indices? Is this an array element swap method?)
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    1. COThank you snickers.
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    2. COPlease review, I have added a few more issues and compiled it all at the bottom. I know you're still learning, but in the future you'll want to follow through exactly what your program is going to do by making a pretend 2D array and running the methods with sample radius', or similar practices.
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    3. COAlso, if I have satisfied your question, please mark my answer as accepted so we do not receive duplicate answers.
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