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    <p>I know it's not a good idea just to provide code, but I was intrigued by this question. Here's how I would do it:</p> <pre><code>$d = 0.3; $random = array(); // Populate the original array for ($n=1; $n &lt;= 10; $n++) { $arr[] = $n; } $count = count($arr); // Loop through array foreach (array_keys($arr) as $key) { if (!isset($prev_key)) { $prev_key = array_rand($arr); } $possibles = array(); // This stores the possible values echo "Trying: $prev_key"; echo ":\n"; // Loop through the array again and populate $possibles with all possible // values based on the previous values foreach (array_keys($arr) as $n) { if ($arr[$n] &lt; $prev_key - $count * $d || $arr[$n] &gt; $prev_key + $count * $d) { $possibles[] = $n; echo $arr[$n]." is valid\n"; } else { echo $arr[$n]; echo " outside range\n"; } } // If there is nothing outside that range, just return the remaining values if (count($possibles) == 0) { $possibles = array_keys($arr); echo "Nothing within range so just returning whole array\n"; } echo "\n"; // Choose random value from the possible values array $rand_key = $possibles[array_rand($possibles)]; $random[] = $arr[$rand_key]; $prev_key = $arr[$rand_key]; // Unset this value from the original array since we can only use the // values once unset($arr[$rand_key]); } print_r($random); </code></pre> <p>This will produce output like this:</p> <pre><code>Trying: 8: 1 is valid 2 is valid 3 is valid 4 is valid 5 outside range 6 outside range 7 outside range 8 outside range 9 outside range 10 outside range Trying: 2: 1 outside range 3 outside range 4 outside range 5 outside range 6 is valid 7 is valid 8 is valid 9 is valid 10 is valid Trying: 9: 1 is valid 3 is valid 4 is valid 5 is valid 6 outside range 7 outside range 8 outside range 10 outside range Trying: 5: 1 is valid 3 outside range 4 outside range 6 outside range 7 outside range 8 outside range 10 is valid Trying: 10: 1 is valid 3 is valid 4 is valid 6 is valid 7 outside range 8 outside range Trying: 4: 1 outside range 3 outside range 6 outside range 7 outside range 8 is valid Trying: 8: 1 is valid 3 is valid 6 outside range 7 outside range Trying: 3: 1 outside range 6 outside range 7 is valid Trying: 7: 1 is valid 6 outside range Trying: 1: 6 is valid Array ( [0] =&gt; 2 [1] =&gt; 9 [2] =&gt; 5 [3] =&gt; 10 [4] =&gt; 4 [5] =&gt; 8 [6] =&gt; 3 [7] =&gt; 7 [8] =&gt; 1 [9] =&gt; 6 ) </code></pre> <p>The only drawback is that since it randomly gets rows, there is a chance that the values near the end may not be outside the defined range. By my tests, this happens to about 4% using the above <code>$d = 0.25</code> and 1000 values. One way to get around this is just to insert these values back in at random places instead of appending them like I have done.</p> <p>Also note, this method is not that efficient. It has to loop through the array <code>count($arr) ^ 2</code> times. So for 1000 values, you're looking at 1,000,000 iterations. Fortunately the array gets progressively smaller.</p>
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    1. POMath & php: FAST sort of an array [1..N] in a special way
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    1. COIt's funny how an awesome answer like this gets 1 or 2 upvotes while something like [this](http://stackoverflow.com/a/18069251/811240) gets 6... Oh Stack Overflow, you crazy website.
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    2. COIf I could I would add +10. Thank you for your answer. I expected there will be more answers and a big discussion. My fault I didn't put my code (doesn't exist yet). Thank you.
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