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    <p>found the solution using 7-Zip-JBinding</p> <p>just need to use ByteArrayInputStream ,this so far worked for a small file</p> <p>pass a archive as argument to get all files inside printed</p> <p>file ExtractItemsSimple.java</p> <pre><code>import java.io.IOException; import java.io.RandomAccessFile; import net.sf.sevenzipjbinding.ISevenZipInArchive; import net.sf.sevenzipjbinding.SevenZip; import net.sf.sevenzipjbinding.SevenZipException; import net.sf.sevenzipjbinding.impl.RandomAccessFileInStream; import net.sf.sevenzipjbinding.simple.ISimpleInArchive; import net.sf.sevenzipjbinding.simple.ISimpleInArchiveItem; public class ExtractItemsSimple { public static void main(String[] args) { RandomAccessFile randomAccessFile = null; ISevenZipInArchive inArchive = null; try { randomAccessFile = new RandomAccessFile(args[0], "r"); inArchive = SevenZip.openInArchive(null, // autodetect archive type new RandomAccessFileInStream(randomAccessFile)); ISimpleInArchive simpleInArchive = inArchive.getSimpleInterface(); for (ISimpleInArchiveItem item : simpleInArchive.getArchiveItems()) { final int[] hash = new int[] { 0 }; if (!item.isFolder()) { System.out.println(ArchieveInputStreamHandler.slurp(new ArchieveInputStreamHandler(item).getInputStream(),1000)); } } } catch (Exception e) { System.err.println("Error occurs: " + e); System.exit(1); } finally { if (inArchive != null) { try { inArchive.close(); } catch (SevenZipException e) { System.err.println("Error closing archive: " + e); } } if (randomAccessFile != null) { try { randomAccessFile.close(); } catch (IOException e) { System.err.println("Error closing file: " + e); } } } } } </code></pre> <p>file ArchieveInputStreamHandler.java</p> <pre><code>import java.io.ByteArrayInputStream; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.io.Reader; import java.io.UnsupportedEncodingException; import net.sf.sevenzipjbinding.ISequentialOutStream; import net.sf.sevenzipjbinding.SevenZipException; import net.sf.sevenzipjbinding.simple.ISimpleInArchiveItem; public class ArchieveInputStreamHandler { private ISimpleInArchiveItem item; private ByteArrayInputStream arrayInputStream; public ArchieveInputStreamHandler(ISimpleInArchiveItem item) { this.item = item; } public InputStream getInputStream() throws SevenZipException{ item.extractSlow(new ISequentialOutStream() { @Override public int write(byte[] data) throws SevenZipException { arrayInputStream = new ByteArrayInputStream(data); return data.length; // Return amount of consumed data } }); return arrayInputStream; } //got from http://stackoverflow.com/questions/309424/read-convert-an-inputstream-to-a-string public static String slurp(final InputStream is, final int bufferSize){ final char[] buffer = new char[bufferSize]; final StringBuilder out = new StringBuilder(); try { final Reader in = new InputStreamReader(is, "UTF-8"); try { for (;;) { int rsz = in.read(buffer, 0, buffer.length); if (rsz &lt; 0) break; out.append(buffer, 0, rsz); } } finally { in.close(); } } catch (UnsupportedEncodingException ex) { /* ... */ } catch (IOException ex) { /* ... */ } return out.toString(); } } </code></pre>
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