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  1. POMidpoints of matrix rows depending on certain conditions Matlab
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    <p>I have a matrix A with size 10x100 as shown below. What I want to do is:</p> <ol> <li>I'll work row by row in which for each row I'll check the data of each coloumn in this row</li> <li>Let's say I'm now in the first col cell in the first row. I'll check if the value is zero I'll move to the next col, and so on till I found a col having a non-zero value and save its col number e.g. col 3 "this means that col 1&amp;2 were zeros"</li> <li>Now I'm in the first non zero col in row1, I'll move to the next col till I find a col with zero value. I'll fetch the col just before this zero one which must be a non-zero one and save it. e.g col 7 "this means that col4&amp;5&amp;6 are non-zeros and col8 is zero"</li> <li>Now I want to save the median middle col between this two columns e.g col3 and col7 then the middle col is col5 so I'll save the index row1_col5. if there are two middle values then any of them is fine.</li> <li>I'll then move to the next col till I find a non-zero col "do the same steps from 2-->5" till the first row is finished.</li> <li>Move to the next row and start over again from step 2-->5.</li> <li>There are two rules: -The first one is that I'll get the middle index of non-zero consecutive values only if there is a minimum of 3 non-zero consecutive values, if there are two non-zero consecutive value then the middle will not be calculated -The second one is that if the number of zero consecutive values are less than 3 then they will be ignored and will be considered as non-zero values. e.g in the below example the first row middle values are col5 and col11. In row2 col5 is counted, while no cols in row3 satisfy this conditions , and in row4 col6 or col7 will be counted.</li> <li>After finishing all the rows want to have a vector or array holding the positions of all the middle indexes e.g row1_col5 row1_col17 row2_col_10 and so on.</li> </ol> <p>example:</p> <pre><code>A = [ 0 0 0 2 4 1 0 0 0 1 3 2; 0 0 0 5 1 1 1 1 0 0 0 1; 0 3 4 1 0 3 1 2 0 0 1 3; 0 0 0 0 1 3 4 5 0 0 0 0]; </code></pre> <p>for the first row the middle value will be 5 and 11 and so on So if anyone could please advise how can I do this with least processing as this can be done using loops but if there is more efficient way of doing it? Please let me know if any clarification is needed.</p>
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