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POHow do I optionally match an additional substring with Python regular expressions?
 

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  1. POHow do I optionally match an additional substring with Python regular expressions?
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    <p>I have a bunch of code in a text file on my computer. I'm interested in two different types of codes in the file. They are:</p> <pre><code>&lt;string&gt;objectiwant1 &lt;string2&gt;objectiwant2&lt;/string2&gt;&lt;/string&gt; </code></pre> <p>and</p> <pre><code>&lt;string&gt;objectiwant1 &lt;/string&gt; </code></pre> <p>The first one would return [(objectiwant1, objectiwant2)] (with more tuples if they exist) while the second one would return [(objectiwant1, None)].</p> <p>I'm trying to create a regular expression and the flawed code I have so far looks something like this:</p> <pre><code>regularexpression = r'&lt;string&gt;(.*) &lt;string2&gt;(.*)&lt;/string2&gt;' </code></pre> <p>I'm using "re.findall(regularexpression, file)" to return the data. Which returns what I want only if both string and string2 are used. Using:</p> <pre><code>regularexpression = r'&lt;string&gt;(.*) (&lt;string2&gt;(.*)&lt;/string2&gt;)|(&lt;/string&gt;) </code></pre> <p>Returns everything within the larger parentheses, sometimes twice (as opposed to only the data within (.*), which are necessary to seperate the statements I want to compare with the OR operator.</p> <p>I'm wondering whether or not there is something I could use to separate the parenthesis which wouldn't cause re.findall to output data twice and output so much data at once.</p> <p>I'm also wondering whether there is a way to use regex to output data if a statement is not fulfilled (so if the objectiwant2 doesn't exist, I get to choose what the output is).</p> <p>Thank you in advance.</p>
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