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POWhy does this scoping example from ANSI Common Lisp not work as expected?
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2013-07-28T03:36:18.907
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2013-07-28T06:02:47.590
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I'm new to lisp and going through ANSI Common Lisp by Paul Graham and one of the exercises is to define a function like apply where any number printed out before it returns will be printed by default in octal. I tried the following: <pre><code>(let ((*print-base* 8)) (defun like-apply (&rest args) (apply #'apply args))) </code></pre> But it didn't work as expected: <pre><code>(like-apply #'princ '(8)); returns 8 8 (expecting 10 8) </code></pre> The following however works: <pre><code>(defun apply8 (&rest args) (let ((*print-base* 8)) (apply #'apply args))) </code></pre> Returns correctly: <pre><code>(apply8 #'princ '(8)); returns 10 8 (as expected) </code></pre> So my question is why does the second example work, but not the first one? Both seem to manipulate the <code>*print-base*</code> variable.
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<common-lisp><scoping>
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Why does this scoping example from ANSI Common Lisp not work as expected?
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