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    <p>It is sufficient to simply increment the counters:</p> <pre><code>class Sparring(): def __init__(self, mywins = 0, hiswins = 0): self.mywins = mywins self.hiswins = hiswins def my_score(self): self.mywins += 1 def his_score(self): self.hiswins += 1 @property def best (self): return max ( [self.mywins, self.hiswins] ) </code></pre> <p>You need the function "best" for your check 'fight1 != 2', which now should red 'fight1.best != 2'. Your program could read:</p> <pre><code>def fight_match(): print "Okay you're in the ring, ready to go three rounds with this dude" print "He throws a left hook, which way will you dodge?" dodge = raw_input() fight1 = Sparring() while fight1.best != 2: if 'right' in dodge: print "Nice job, you knocked him out!" fight1.my_score() else: print 'Oh no he knocked you out' fight1.his_score() </code></pre> <p>Another thing is, that you will probably want to move your input into the while loop:</p> <pre><code> fight1 = Sparring() while fight1.best != 2: dodge = raw_input() if 'right' in dodge: print "Nice job, you knocked him out!" fight1.my_score() else: print 'Oh no he knocked you out' fight1.his_score() </code></pre> <p>In order to answer your comment, I will provide a sample implementatio of a whole fight:</p> <pre><code>import random class Fight: def __init__ (self): self.scores = [0, 0] def heScores (self): self.scores [1] += 1 def youScore (self): self.scores [0] += 1 @property def best (self): return max (self.scores) @property def winner (self): return 'You win.' if self.scores [0] &gt; self.scores [1] else 'He wins.' fight = Fight () print ('Fight begins.') question, answer = 'left', 'right' while fight.best != 2: if random.randint (0, 1): question, answer = answer, question if answer in input ('He throws a {} hook, which way will you dodge? '.format (question) ): print ('Nice job, you knocked him out.') fight.youScore () else: print ('Oh no, he knocked you out.') fight.heScores () print (fight.winner) </code></pre> <p>Just for completeness's sake and in order to do some code golfing, this is the one-liner which does the same:</p> <pre><code>_ = [print ('Fight!'), print ('You won.' if (lambda a, b: (lambda a, *b: a (a, *b) ) ( (lambda a, b, c, d, e: e if max (e) == 2 else a (a, b, c, c (b), [print ('Nice job, you knocked him out.'), (1 + e [0], 0 + e [1] )] [1] if d [1] in input ('He throws a {} hook, which way will you dodge? '.format (d [0] ) ) else [print ('Oh no, he knocked you out.'), (0 + e [0], 1 + e [1] )] [1] ) ), b, a, a (b), (0, 0) ) ) ( (lambda a: ('left', 'right') if a.randint (0, 1) else ('right', 'left') ), __import__ ('random') ) [0] == 2 else 'He won.') ] </code></pre>
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    1. CO@Hyperboreous This is great! However I forgot to explain that I want to make the match best out of 3. So I need a way to check if either 'mywins' or 'hiswins' have reached 2, then stop there.
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    2. COThe while loop will indeed stop, once either one has scored two hits.
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    3. COIf you want to know who is the winner, add: `def winner (self): return 'me' if self.mywins > self.hiswins else 'him'`
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