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POSymfony 2 Doctrine: OrderBy - GroupBy Max Element with Joins
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2013-07-25T17:01:59.757
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2013-08-24T20:38:34.003
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2013-08-12T12:11:11.500
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My problem is Doctrine and SQL GroupBy with Order By So a little description there is a shop(s), the shop has articles(a) and there is an entity visit counter(vc) to count the visits of different things, also used for shop and article. I want a list of articles(top articles), but just the most visited article for each shop. <pre><code> class Shop { private $id; private $name; private $is_published; ... /** * OneToMany articles */ private $articles; } class Article { private $id; private $name; private $is_published; ... /* ManyToOne Shop*/ private $shop; } class VisitCounter { private $id; private $object_type; //0 for Article, 1 for Shop, 2 for Category private $object_id; ... private $nr_alltime_visits; } </code></pre> Then I have tried with the following query in the article repository: <pre><code> $query = $this->createQueryBuilder('a', 's', 'vc') ->select('a, s') ->leftJoin('a.shop', 's') ->leftJoin('ProjMyBundle:VisitCounter', 'vc', 'WITH', 'vc.object_type = 0 AND cs.object_id= a.id') ->where('a.is_published = 1 AND s.is_published = 1) ->orderBy('vc.nr_alltime_visits', 'DESC') ->groupBy('a.shop'); </code></pre> But for I didn't get the articles expected, if I remove the group by I get the right articles but more than 1 per Shop. Any Ideas? Before this problem I had a field in Shop and Article(private $nr_visits), and then I had something like this(could help someone in the future): <pre><code> $query = $this->createQueryBuilder('a', 's') ->select('a, s') ->where('a.is_published = 1 AND s.is_published = 1') ->leftJoin('a.shop', 's') ->groupBy('a.shop') ->orderBy('nr_visits', 'DESC'); $query->andWhere('a.nr_visits = (SELECT MAX(a2.nr_visits) as nr_visits2 FROM ProjMyBundle:Article AS a2 WHERE a2.is_published = 1 AND a2.shop=a.shop GROUP BY a2.shop)'); </code></pre>
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<php><symfony><doctrine2>
Title
Symfony 2 Doctrine: OrderBy - GroupBy Max Element with Joins
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