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  1. PO
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    <pre><code>while ((line = reader.readLine()) != null){ sb.append(line + "\n"); } </code></pre> <p>instead try</p> <pre><code>while ((line = reader.readLine()) != null){ sb.append(line); json = sb.toString().substring(0, sb.toString().length()-1); } </code></pre> <p>Follow this method for getting json object:</p> <pre><code> public JSONObject getJSONObjFromUrl(String url, List&lt;NameValuePair&gt; params) { System.out.println("url:: "+url ); System.out.println("params:: "+ params +" " +params.get(0) ); // Making HTTP request try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); httpPost.setEntity(new UrlEncodedFormEntity(params)); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { BufferedReader reader = new BufferedReader(new InputStreamReader( is, "iso-8859-1"), 8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line); } is.close(); json = sb.toString().substring(0, sb.toString().length()-1); // Log.e("JSON:: ", json); } catch (Exception e) { Log.e("Buffer Error", "Error converting result " + e.toString()); } // try parse the string to a JSON object try { jObj = new JSONObject(json); } catch (JSONException e) { Log.e("JSON Parser", "Error parsing data " + e.toString()); } // return JSON String return jObj; } </code></pre>
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    1. POorg.json.JSONException: Value of type java.lang.String cannot be converted to JSONObject
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    1. USMohammod Hossain
    1. USMohammod Hossain
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    1. POorg.json.JSONException: Value of type java.lang.String cannot be converted to JSONObject
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    1. COi delete the \n but your trick with substring make an error : debug JSONException(4461): org.json.JSONException: Unterminated object at character 242 of
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      1. USJeremy Piednoel
    2. COgo to the site http://json.parser.online.fr/. check your json is corrent or not
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      1. USMohammod Hossain
    3. CONice very good site i found the mistake it was a space between [" "] in my JSON, i update my question. TYVM !
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      1. USJeremy Piednoel
 

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Guidance
A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

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