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PORemoving hash comments that are not inside quotes
 

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    <p>I am using python to go through a file and remove any comments. A comment is defined as a hash and anything to the right of it <em>as long as the hash isn't inside double quotes</em>. I currently have a solution, but it seems sub-optimal:</p> <pre><code>filelines = [] r = re.compile('(".*?")') for line in f: m = r.split(line) nline = '' for token in m: if token.find('#') != -1 and token[0] != '"': nline += token[:token.find('#')] break else: nline += token filelines.append(nline) </code></pre> <p>Is there a way to find the first hash not within quotes without for loops (i.e. through regular expressions?)</p> <p>Examples:</p> <pre><code>' "Phone #":"555-1234" ' -&gt; ' "Phone #":"555-1234" ' ' "Phone "#:"555-1234" ' -&gt; ' "Phone "' '#"Phone #":"555-1234" ' -&gt; '' ' "Phone #":"555-1234" #Comment' -&gt; ' "Phone #":"555-1234" ' </code></pre> <hr> <p>Edit: Here is a pure regex solution created by user2357112. I tested it, and it works great:</p> <pre><code>filelines = [] r = re.compile('(?:"[^"]*"|[^"#])*(#)') for line in f: m = r.match(line) if m != None: filelines.append(line[:m.start(1)]) else: filelines.append(line) </code></pre> <p>See his reply for more details on how this regex works.</p> <p>Edit2: Here's a version of user2357112's code that I modified to account for escape characters (\"). This code also eliminates the 'if' by including a check for end of string ($):</p> <pre><code>filelines = [] r = re.compile(r'(?:"(?:[^"\\]|\\.)*"|[^"#])*(#|$)') for line in f: m = r.match(line) filelines.append(line[:m.start(1)]) </code></pre>
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