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    <p><strong><a href="http://jsfiddle.net/kCqaG/1/" rel="nofollow">Here is my solution</a></strong>, much like @robert king 's (as I discovered after tackling the problem myself) except mine is complete (already is capable of not counting overlapping patterns) and optimised (as much as I can).</p> <p>Also, returns a map of objects, so you can enumerate over it and only pull out patterns of size X, or ones that repeated Y times etc.</p> <p><br/> The following line (with the below function)</p> <pre class="lang-js prettyprint-override"><code>getPatterns([1,2,1,1,1,1,0,2,1,2,3,10,12,54,10,12]).showRepeated(); </code></pre> <p>will result in this;</p> <pre class="lang-js prettyprint-override"><code>1 2 found 2 times 2 1 found 2 times 1 1 found 2 times 10 12 found 2 times </code></pre> <p><br/> <strong>CODE</strong></p> <pre class="lang-js prettyprint-override"><code>function getPatterns(input, generateAll) { var patternMap = new getPatterns.presentation(); var generated = []; var patternObj; var start; //for each item for (var index = 0; index &lt; input.length; ++index) { //open a new slot for a new pattern start at this index generated.push(''); start = 0; //unless told to generate all //skip patterns that cant possibly be repeated //(i.e. longer than half the input length) if (!generateAll &amp;&amp; generated.length &gt; input.length / 2) start = generated.length - Math.floor(input.length / 2); //test patterns we have generated for this index for (var index2 = start; index2 &lt; generated.length; ++index2) { //generate a fresh lot of patterns for this index generated[index2] += ' ' + input[index]; //unless told to generate all, dismiss patterns of length 1 if (!generateAll &amp;&amp; index2 == generated.length - 1) break; //try to fetch a pre-existing pattern, O(1) patternObj = patternMap[generated[index2]]; //if this is a new pattern if (!patternObj) { //generate an object patternMap[generated[index2]] = { lastSeen : index, count : 1, size : generated.length - index2 }; continue; } //unless told to generate all, skip patterns that overlap with themselves if (!generateAll &amp;&amp; index - patternObj.lastSeen &lt; patternObj.size) continue; //this pattern has repeated! update the object data ++patternObj.count; patternObj.lastSeen = index; } } return patternMap; } //just for a function prototype getPatterns.presentation = function() {}; getPatterns.presentation.prototype = { showRepeated : function() { var patternObj; for (var pattern in this) { patternObj = this[pattern]; if (patternObj.count &gt; 1) console.log(pattern + '\tfound ' + patternObj.count + ' times'); } } }; </code></pre>
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